SQL将一列转换成一行,并将这一行形成新的列
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SQL部分-----
- .查询出来要转换的数据
SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1
数据如图:
2.将查询到的数据转换成行,以逗号隔开,以【】包裹
SELECT STUFF((SELECT \'[\' + name + \'],\' FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a FOR XML PATH(\'\') ), 1,0, \'\') AS Name
如图:
3,去掉最后一个逗号
SELECT LEFT(a.Name,LEN(a.Name)-1) AS Name FROM (SELECT STUFF((SELECT \'[\' + name + \'],\' FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a FOR XML PATH(\'\') ), 1,0, \'\') AS Name ) AS a
如图:
4,这一行形成新的列,用PIVOT实现
SELECT * FROM ( select sellerid,pay_type_name,cast(sum(amount) as decimal(18,2)) as payamout from ( SELECT distinct oi.order_guid,ss.SellerId,bs.name AS pay_type_name,op.amount FROM dbo.shop_sellers AS ss LEFT JOIN dbo.order_item oi ON ss.SellerId=oi.tracking_id LEFT JOIN dbo.order_list ol ON ol.order_guid = oi.order_guid LEFT JOIN dbo.order_pay op ON ol.order_guid=op.order_guid LEFT JOIN dbo.base_pay_type bs ON op.pay_type_id=bs.pay_type_id INNER JOIN dbo.shops s ON s.ShopGuid=ol.owner WHERE bs.is_enabled=1 AND op.is_received=1 AND order_status=\'finished\' and pay_status=\'paid\' and s.ShopId IN(SELECT ShopId FROM dbo.shops WHERE 1=1 and shopid=15 or ParentShopId=15) AND ol.order_time between \'2018-01-17\' and \'2018-08-17 23:59:59\') a GROUP BY SellerId,pay_type_name) AS PA PIVOT(MAX( payamout ) FOR pay_type_name IN ([现金],[支付宝],[微信支付],[会员卡],[康品汇会员卡],[银联扫码支付]))PPA
如图:
C#后台代码,先将一列转换成一行,以逗号隔开,【】包裹
string SQL = "SELECT LEFT(a.Name,LEN(a.Name)-1) AS Name FROM (SELECT STUFF((SELECT \'[\' + name + \'],\'
FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a FOR XML PATH(\'\') ), 1, 0, \'\') AS Name ) AS a"; DataTable dt = dbAccess.ExecuteTable(SQL); string filwes = dt.Rows[0]["name"].ToString();
得到的结果如上面标题3,然后拼接SQL,将filwes作为参数输入下面SQL语句
SELECT * FROM (
select sellerid,pay_type_name,cast(sum(amount) as decimal(18,2)) as payamout from (
SELECT distinct oi.order_guid,ss.SellerId,bs.name AS pay_type_name,op.amount
FROM dbo.shop_sellers AS ss
LEFT JOIN dbo.order_item oi ON ss.SellerId=oi.tracking_id
LEFT JOIN dbo.order_list ol ON ol.order_guid = oi.order_guid
LEFT JOIN dbo.order_pay op ON ol.order_guid=op.order_guid
LEFT JOIN dbo.base_pay_type bs ON op.pay_type_id=bs.pay_type_id
INNER JOIN dbo.shops s ON s.ShopGuid=ol.owner
WHERE bs.is_enabled=1 AND op.is_received=1 AND order_status=\'finished\' and pay_status=\'paid\'
and s.ShopId IN(SELECT ShopId FROM dbo.shops WHERE 1=1 {1}) {2}) a
GROUP BY SellerId,pay_type_name) AS PA PIVOT(MAX( payamout ) FOR pay_type_name IN (‘“+filwes+”’))PPA
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