MongoDB 基本语法

Posted 2020-12-23 d-w

1、数据准备

　　1、MongoDB数据，工具为：Robo 3T

　　

 mongo-data

　　2、mysql数据

　　

 MySQL

2、新增语句

方法	说明	语法	备注
新增	MongoDB	db.getCollection(\'user\').insert({"userId" : "014","uclass" : "B","name" : "Back","age" : 11,"email" : "[e-mail]","birthday" : ISODate("2018-07-31T03:46:13.885Z"),"dataStatus" : 1});
	MySQL	INSERT INTO `sz-temp`.`user` (`userId`, `uclass`, `name`, `age`, `email`, `birthday`, `dataStatus`) VALUES (\'014\', \'B\', \'Back13\', \'20\', \'[e-mail]\', \'2013-07-31 11:46:13\', \'0\');

3、删除语句

方法	说明	语法	备注
删除	MongoDB	db.getCollection(\'user\').remove({"userId":"014"});
	MySQL	delete from user where userId = \'014\';

4、修改语句

方法	说明	语法	备注
修改	MongoDB	db.getCollection(\'user\').update({"userId":"013"}, {$set:{"email":"[e-mail]", "age":20}});
	MySQL	update user set email = \'[e-mail]\', age = 20 where userId = \'013\';

5、查询语句

查询方法	说明	语法	备注
查询所有	MongoDB	db.getCollection(\'user\').find({});
	MySQL	select * from user;
查询条件：=	MongoDB	db.getCollection(\'user\').find({"uclass":"A"});
	MySQL	select * from user where uclass = \'A\';
查询条件：like	MongoDB	select * from user where name like \'%Ba%\';
	MySQL	db.getCollection(\'user\').find({"name":/Ba/});
查询条件：distinct	MongoDB	select distinct uclass from user u;
	MySQL	db.getCollection(\'user\').distinct("name");
查询条件：$gt	MongoDB	db.getCollection(\'user\').find({"age":{$gt:16}});	greater than  >
	MySQL	select * from user where age >16;
查询条件：$gte	MongoDB	db.getCollection(\'user\').find({"age":{$gte:16}});	gt equal  >=
	MySQL	select * from user where age >= 16;
查询条件：$lt	MongoDB	db.getCollection(\'user\').find({"age":{$lt:16}});	less than  <
	MySQL	select * from user where age < 16;
查询条件：$lte	MongoDB	db.getCollection(\'user\').find({"age":{$lte:16}});	lt equal  <=
	MySQL	select * from user where age <= 16;
查询条件：$ne	MongoDB	db.getCollection(\'user\').find({"age":{$ne:16}});	not equal  !=
	MySQL	select * from user where age != 16;
查询条件：$eq	MongoDB	db.getCollection(\'user\').find({"age":{$eq:16}});等效于：db.getCollection(\'user\').find({"age":16});	equal  =
	MySQL	select * from user where age = 16;
查询条件：in	MongoDB	db.getCollection(\'user\').find({"uclass":{$in:[\'A\', \'B\']}});
	MySQL	select * from user where uclass in (\'A\', \'B\');
查询条件：and	MongoDB	db.getCollection(\'user\').find({"uclass":"B", "age":{$gt:16}});
	MySQL	select * from user where uclass = \'B\' and age > 16;
查询条件：or	MongoDB	db.getCollection(\'user\').find({$or:[{"uclass":"A"},{"class":"B"}]});
	MySQL	select * from user where uclass = \'A\' or  uclass = \'B\';
查询条件：时间	MongoDB	db.getCollection(\'user\').find({"birthday":{$gt: new Date("2008-08-14T06:24:40.110Z"), $lt: new Date("2015-08-14T06:14:40.089Z")}});
	MySQL	select * from user where birthday > \'2008-08-14 06:24:40\' and birthday < \'2015-08-14 06:14:40\';
查询条数：count	MongoDB	db.getCollection(\'user\').find({"uclass":"A"}).count();
	MySQL	select count(1) from user where uclass = \'A\';
查询条件：sort升序	MongoDB	db.getCollection(\'user\').find({}).sort({"age":1});
	MySQL	select * from user order by age asc;
查询条件：sort降序	MongoDB	db.getCollection(\'user\').find({}).sort({"age":-1});
	MySQL	select * from user order by age desc;
聚合查询：count单列	MongoDB	db.getCollection(\'user\').aggregate([{$group:{_id:"$uclass",num:{$sum:1}}}]);
	MySQL	select uclass, count(1) as num from user group by uclass;
聚合查询：count多列	MongoDB	db.getCollection(\'user\').aggregate([{$group:{_id:{uclass:"$uclass", age:"$age"},num:{$sum:1}}}]);
	MySQL	select uclass, age, count(1) as num from user group by uclass, age;
分页查询：limit n	MongoDB	db.getCollection(\'user\').find({}).limit(5);	查询前n条
	MySQL	select * from user limit 5;
分页查询：limit m,n	MongoDB	db.getCollection(\'user\').find({}).limit(5).skip(5);	查询n条，从第m条开始
	MySQL	select * from user limit 5,5;
查询指定字段	MongoDB	db.getCollection(\'user\').find({}, {userId:1, name:1});	第一个{}为查询条件
	MySQL	select userId, name from user;
排查指定字段	MongoDB	db.getCollection(\'user\').find({}, {dataStatus:0, _id:0});	第一个{}为查询条件
	MySQL	无

6、参考网站

　　本文摘自  https://www.cnblogs.com/mao2080/p/9570909.html

　　http://www.runoob.com/mongodb/mongodb-aggregate.html

　　https://www.jianshu.com/p/5e870132ca7c