sqlzoo刷题 SELECT within SELECT Tutorial
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SELECT within SELECT Tutorial
5.Germany (population 80 million) has the largest population of the countries in Europe. Austria (population 8.5 million) has 11% of the population of Germany.
Show the name and the population of each country in Europe. Show the population as a percentage of the population of Germany.
The format should be Name, Percentage for example:
name | percentage |
---|---|
Albania | 3% |
Andorra | 0% |
Austria | 11% |
... | ... |
select name,concat(cast(round(100*population/(select population from world where name=\'Germany\'),0) as int),\'%\') from world where continent=\'Europe\'
note:
CONCAT() 函数用于将多个字符串连接成一个字符串,语法简单就是:CONCST(str1,str2,…)
两种返回结果:
- 然后就返回连接后的字符串
- 其中有一个参数为NULL ,则返回值为 NULL
这里有两个注意的点
① The solution shown only works with mysql - you can switch engines at the top of the page.
For SQL Server use ROUND(x,0) in place of ROUND(x)
round需要在后面加一个0,否则会报错
② 需要用cast将round的结果转换为int,否则会多一串0
6.Which countries have a GDP greater than every country in Europe? [Give the name only.] (Some countries may have NULL gdp values)
select name from world where gdp >all (select gdp from world where gdp>0 and continent=\'Europe\')
note : 使用all结果会包含null的情况,所以要加上gdp>0来限定
7.Find the largest country (by area) in each continent, show the continent, the name and the area:
SELECT continent,name, area FROM world x where area>=(select max(area) from world y where y.continent=x.continent)
note :使用聚合函数,自动去除了空值的行,所以可以不加area>0来限定
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