整理oracle 树形查询

Posted 2020-12-05 ✧*꧁一品堂.技术学习笔记꧂*✧.

注：本文参考了《整理oracle 树形查询》

sql树形递归查询是数据库查询的一种特殊情形，也是组织结构、行政区划查询的一种最常用的的情形之一。下面对该种查询进行一些总结：

create table JD2_SUPERVISE_MATTER
(
  id                     NUMBER(10) not null,
  pid                    NUMBER(10),
  data_model_id          NUMBER(10),
  code                   VARCHAR2(30),
  name                   VARCHAR2(30),
  descript               VARCHAR2(50),
  flag_notic_budget_unit CHAR(1),
  flag_notic_busi_dept   CHAR(1),
  busi_dept_name         VARCHAR2(30),
  orderid                NUMBER(10)
)

alter table JD2_SUPERVISE_MATTER
  add constraint PK_JD2_SUPERVISE_MATTER primary key (ID)

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (542, 362, null, \'ZCJH\', \'支出计划\', null, null, null, null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (543, 542, null, \'YKJH\', \'用款计划申请\', null, null, null, null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (544, 542, null, \'YKJHHZ\', \'用款计划汇总审核\', null, null, null, null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (481, 382, 361, \'ZJZFSP\', \'直接支付申请汇总审批\', null, \'0\', \'1\', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (361, null, 302, \'YSBZ\', \'预算编制\', null, \'1\', \'0\', \'\', null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (363, 361, 21, \'NCYS\', \'年初预算\', null, \'1\', \'1\', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (362, null, 101, \'YSZX\', \'预算执行\', null, \'0\', \'1\', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (381, 362, 61, \'SRZX\', \'收入执行\', null, \'0\', \'1\', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (382, 362, 101, \'ZCZX\', \'支出执行\', null, \'0\', \'0\', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (383, 382, null, \'ZFSP\', \'支付审批\', null, \'1\', \'0\', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (384, 383, 281, \'ZJZF\', \'直接支付\', null, \'0\', \'1\', null, null);

insert into JD2_SUPERVISE_MATTER (ID, PID, DATA_MODEL_ID, CODE, NAME, DESCRIPT, FLAG_NOTIC_BUDGET_UNIT, FLAG_NOTIC_BUSI_DEPT, BUSI_DEPT_NAME, ORDERID)
values (521, null, 221, \'YSJH\', \'预算计划\', null, \'0\', \'1\', null, null);

1、查找某个节点下面子孙节点

select * from JD2_SUPERVISE_MATTER start with id=361 connect by prior id=pid

2、查找节点的祖先节点

select * from JD2_SUPERVISE_MATTER start with id=361 connect by prior pid=id

在树形结构节点很多的情况一下，一般会采用异步刷新的方式进行，在默认加载的情况下，会展开到某个层级。这种情况下，不但要获取某个节点的祖先节点，还需要获取祖先节点的兄弟节点，在这种情况下可以通过level进行

select id,pid,level from JD2_SUPERVISE_MATTER where level>1
connect by prior id=pid start with id=361      order by level

显示出树的级别查询

select id,rpad(\' \',(level-1)*4)||name,code,level from JD2_SUPERVISE_MATTER
 connect by pid = prior id   start with pid is null;