HackerRankSQL3
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1、Higher Than 75 Marks
Query the Name of any student in STUDENTS who scored higher than 75 Marks. Order your output by the last three charactersof each name. If two or more students both have names ending in the same last three characters (i.e.: Bobby, Robby, etc.), secondary sort them by ascending ID.
The STUDENTS table is described as follows:
Sample Output
Ashley
Julia
Belvet
Explanation
Only Ashley, Julia, and Belvet have Marks > 75. If you look at the last three characters of each of their names, there are no duplicates and ‘ley‘ < ‘lia‘ < ‘vet‘.
select Name from STUDENTS WHERE Marks > 75 order by right(Name, 3), ID ASC;
2、Employee Names
Write a query that prints a list of employee names (i.e.: the name attribute) from the Employee table in alphabetical order.
Input Format
The Employee table containing employee data for a company is described as follows:
where employee_id is an employee‘s ID number, name is their name, months is the total number of months they‘ve been working for the company, and salary is their monthly salary.
Sample Output
Angela Bonnie Frank Joe Kimberly Lisa Michael Patrick Rose Todd
select Name from Employee order by CONVERT (Name USING utf8);
3、Employee Salaries
Write a query that prints a list of employee names (i.e.: the name attribute) for employees in Employee having a salary greater than $2000 per month who have been employees for less than 10 months. Sort your result by ascending employee_id.
Input Format
The Employee table containing employee data for a company is described as follows:
where employee_id is an employee‘s ID number, name is their name, months is the total number of months they‘ve been working for the company, and salary is the their monthly salary.
Sample Input
Sample Output
Angela Michael Todd Joe
select Name from Employee where salary > 2000 and months<10 order by employee_id;
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