ORACLE常见问题收集

Posted 2020-11-09 沿海地带

1.Java代码执行oracle，update和insert语句卡住不动

解决方法：造成这样的情况原因在于你之前执行了update或insert操作但你并没有commit，导致你操作的这条记录被oracle锁住，后面就无法update或insert。

1：可能你是在PLSQL中操作的，commit一下 
2：查询锁定：SELECT s.sid, s.serial# FROM v$locked_object lo, dba_objects ao, v$session s WHERE ao.object_id = lo.object_id AND lo.session_id = s.sid;
　  删除锁定：ALTER system KILL session ‘SID,serial‘

2.ORACLE插入时间对象

insert into SY_COMM_CONFIG (CONF_ID, S_MTIME )
values(‘12345‘,to_char(sysdate,‘YYYY-MM-DD HH24:MI:SS‘) 

选择ORACLE里面的系统时间 SELECT SYSDATE FROM DUAL;

3.CASE  WHEN过滤多行数据

  SELECT TLB_ID, 
                  TO_CHAR(AUDIT_DATE, ‘YYYY-MM-DD HH24:MI:SS‘) AS AUDIT_DATE, 
                  AUDIT_RESULT, 
                  (case 
                  when AUDIT_PROCESS = ‘111‘ then 
                  ‘1‘ /*待处理*/ 
                  when AUDIT_PROCESS in (‘118‘, ‘211‘, ‘212‘, ‘213‘, ‘221‘, ‘222‘, ‘223‘, ‘231‘, ‘239‘, ‘218‘, ‘228‘) then 
                  ‘2‘ /*审核中*/ 
                  when AUDIT_PROCESS in (‘311‘, ‘312‘) then 
                  ‘3‘ /*合同确认中*/    when AUDIT_PROCESS in 
                  (‘411‘, ‘412‘, ‘413‘, ‘414‘, ‘419‘, ‘421‘, ‘422‘) then 
                  ‘4‘ /*放款处理中*/    when AUDIT_PROCESS = ‘423‘ then 
                  ‘5‘ /* 已放款*/    when AUDIT_PROCESS = ‘999‘ then 
                  ‘6‘ /*已结束*/    else    AUDIT_PROCESS 
                  end) as HEAD_PROCESS    from TLB_APPLY_AUDIT_RECORD 
                  where 1 = 1    and TLB_ID = :TLB_ID 
                  and TLB_TYPE = ‘1‘    and AUDIT_RESULT != ‘-1‘ 
                  ORDER BY AUDIT_DATE DESC ;

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