一段程序看不懂,高手帮忙读一下

Posted 2023-04-10

好像是关于读进内存池之类的,其中2个结构体的成员变量看不懂应该不影响阅读
typedef struct _NODE_DATA

char szName[256];
int nNodeID;
int nCalcID;
int nVolGradeID;
int nType;
double fVoltage;
double fPhase;
double fVolreal;
double fVolimag;
double fVolMax;
double fVolMin;
double fP;
double fQ;
NodeData, *PNodeData;

struct SharedBlock;
extern HANDLE ghDataLock;
extern SharedBlock* gpSharedBlock;

//shared data struct
struct SharedBlock

int nFlag;
int nNodeCount;
int nPQNodeCount;
int nPVNodeCount;
int nBranchCount;
char _based(gpSharedBlock) *pNode[1024];
char _based(gpSharedBlock) *pBranch[1024];
;

class CSharedMemApp : public CWinApp

public:
CSharedMemApp();

// Overrides
// ClassWizard generated virtual function overrides
//AFX_VIRTUAL(CSharedMemApp)
public:
virtual BOOL InitInstance();
virtual int ExitInstance();
//AFX_VIRTUAL

//AFX_MSG(CSharedMemApp)
// NOTE - the ClassWizard will add and remove member functions here.
// DO NOT EDIT what you see in these blocks of generated code !
//AFX_MSG
DECLARE_MESSAGE_MAP()
;

HANDLE ghDataLock;
HANDLE ghFileMapping;

BOOL CSharedMemApp::InitInstance()

ghDataLock = ::CreateMutex(NULL, TRUE, "ShareMem Data Mutex");
VERIFY( ghDataLock != NULL );

ghFileMapping = ::CreateFileMapping(
(HANDLE)0xFFFFFFFF, // File handle
NULL, // Security attributes
PAGE_READWRITE, // Protection
0, // Size - high 32 bits
1<<24, // Size - low 32 bits
"NLPowerFlow Data Block"); // Name

VERIFY( ghFileMapping != NULL );
DWORD dwMapErr = GetLastError();

gpSharedBlock = (SharedBlock*) ::MapViewOfFile(
ghFileMapping,
FILE_MAP_ALL_ACCESS, // Read/Write
0, // Offset - high 32 bits
0, // Offset - low 32 bits
0); // Map the whole thing
VERIFY( gpSharedBlock != NULL );

// Only initialize shared memory if we actually created.
if (dwMapErr != ERROR_ALREADY_EXISTS)

memset(gpSharedBlock, 0, sizeof(SharedBlock));


::ReleaseMutex(ghDataLock);

return CWinApp::InitInstance();


bool APIENTRY ReadNodeData(int nIndex, NodeData* pNodeData)

bool bRet = false;
// Make sure the shared memory is available
::WaitForSingleObject(ghDataLock, INFINITE);
if(gpSharedBlock != NULL )

if(nIndex < gpSharedBlock->nNodeCount)

memcpy(pNodeData, gpSharedBlock->pNode[nIndex], sizeof(NodeData));

bRet = true;


::ReleaseMutex(ghDataLock);
return bRet;

错了,最后一个ReadNodeData()函数应该替换成
bool APIENTRY AddtoNodeData(NodeData* pNodeData)

::WaitForSingleObject(ghDataLock, INFINITE);
bool bRet = false;
if(gpSharedBlock != NULL )

if( gpSharedBlock->nNodeCount < 1024 )

char *lpDataBuffer = (char*)gpSharedBlock + sizeof(SharedBlock) +
gpSharedBlock->nNodeCount * sizeof(NodeData);
memcpy(lpDataBuffer, pNodeData, sizeof(NodeData));
gpSharedBlock->pNode[gpSharedBlock->nNodeCount] = (char _based(gpSharedBlock) *)lpDataBuffer;
(gpSharedBlock->nNodeCount)++;
if(pNodeData->nType == 1)

(gpSharedBlock->nPQNodeCount)++;

else if(pNodeData->nType == 2)

(gpSharedBlock->nPVNodeCount)++;

bRet = true;


::ReleaseMutex(ghDataLock);
return bRet;

参考技术A 结构体,只是规定的一种框架.个别成员变量看不懂应该不影响阅读. 这一段程序说的是建立内存影射和获取影射. 参考技术B 搞通信或者网络的吧，所以说啊，写程序一定要加注释的！

请高手帮忙分析下SPSS的多元线性回归结果吧~急啊~~~

下面是线性回归出来的四个图。。。看不懂啊。。。请高手帮个忙，是写在论文里的，所以请稍微详细点说说吧~主要是三个变量和Y的拟合度怎么样，如何看的~~谢谢了~~~

Variables Entered/Removed(b)
Model Variables Entered Variables Removed Method
1 X3, X2, X1(a) . Enter
a All requested variables entered.
b Dependent Variable: Y

Model Summary
Model R R Square Adjusted R Square Std. Error of the Estimate
1 .823(a) .678 .664 4.60955
a Predictors: (Constant), X3, X2, X1

ANOVA(b)
Model Sum of Squares df Mean Square F Sig.
1 Regression 3170.063 3 1056.688 49.731 .000(a)
Residual 1508.604 71 21.248
Total 4678.667 74
a Predictors: (Constant), X3, X2, X1
b Dependent Variable: Y

Coefficients(a)
Model Unstandardized Coefficients Standardized Coefficients t Sig.
B Std. Error Beta
1 (Constant) -4.517 1.517 -2.978 .004
X1 -2.79E-005 .000 -.144 -.174 .863
X2 .076 .008 .693 9.355 .000
X3 7.40E-005 .000 .398 .483 .631
a Dependent Variable: Y
图片

参考技术A 你的回归方法是直接进入法
拟合优度R方等于0.678，表示自变量可以解释因变量的67.8%变化，说明拟合优度还可以。
方差检验表中F值对应的概率P值为0.000，小于显著度0.05，因此应拒绝原假设，说明自变量和因变量之间存在显著的线性关系。
参数检验表中只有自变量X2和常数项的概率P值为0.000，小于显著度0.05，而自变量X1和X3的概率P值大于显著度0.05，说明只有自变量X2对因变量在总体中存在显著的线性关系，X1、X3和因变量在总体中不存在显著的线性关系。
得到的线性方程为：y=-4.517-0.000028X1+0.76X2+0.000074X3（记住这里用的是直接进入法进行拟合方程的，所以即使X1和X3没通过检验，也要放到方程中去）本回答被提问者采纳