javaweb这个功能怎么实现 ajax

Posted 2023-04-08

js有一个如图的数据，怎么在页面中遍历出来

参考技术A 把后台的数据转成json格式就行了 参考技术B 1、如果你传到页面的是java对象，直接用jstl标签或者ognl
2、如果是js对象，用argularjs或者vue

我该怎么用AJAX控件来实现登录的功能？

以前我是弄一个登录的页面，然后加个Session，然后登录后页面跳到主页。

现在我想把登录的框放在一个Update Panel中。在没登录时，点页面上的东西会提示要先登录，登录后Update Panel显示这个用户的基本信息然后页面上的功能也可以用了。

该如何实现？

小弟初学~望高手指点~~

asp.net ajax就可以啊，有update panel的啊

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http://bbs.topsage.com/dispbbs.asp?boardID=121&ID=166512 参考技术A 我会
用javascript 建立
var xmlhttp;
function createxmlhttprequest()
if (window.ActiveXObject)
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");

else if (window.XMLHttpRequest)
xmlhttp=new XMLHttpRequest();


上面的意思就是建立异步连接
function startRequest1()
createxmlhttprequest();
xmlhttp.onreadystatechange=handlestatechange1;
names=document.UserReg.UserName.value;
xmlhttp.open("POST","ajaxtestuser.aspx?names="+names,true);
xmlhttp.send(null);

很好理解 用建立的连接
发送一个数据到你的检查用户名登陆的页面
是密码的话用
xmlhttp.send(*);

function handlestatechange1()
if(xmlhttp.readyState==4)
if(xmlhttp.status==200)
if(xmlhttp.responseText=="1")

document.all.smsg1.style.border='1px #00BE00 solid';

发送了就要处理 当状态(=4就是已经接受)
=200就是返回成功了
你又在你的检查登陆的页面发送值过来
比如
response.write("1")
在这里接受
xmlhttp.responseText
判断
最后你知道怎么做了吧
很简单本回答被提问者采纳 参考技术B 用Update Panel，把login控件放在里面就行了。