1001 A+B Format

Posted 2023-04-08 psogos

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Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

代码长度限制

16 KB

时间限制

400 ms

内存限制

64 MB

comma: 逗号

代码

#include<iostream>
#include<vector>
#include<string>
#include<math.h>
#include<algorithm>
#include<stack>
using namespace std;
stack<char> st;
int main()
    int n,m;
    cin >> n >> m;
    **string s = to_string(n + m); //把相加结果转换为字符串**
    int cnt = 0;//用来计算数字的个数
    for(int i = s.length() - 1; i >= 0; i--) 
        st.push(s[i]);

        if (isdigit(s[i])) //判断为是数字
        
            cnt++;
        
        if (cnt != 0 && cnt % 3 == 0 && i != 0 && isdigit(s[i-1]))
        
            st.push(',');
        
    
   while(!st.empty())
    
        cout << st.top();
        st.pop();
    

    return 0;