postgresql 9.6 建立多列索引测试

Posted 2020-08-19

建立测试表结构

CREATE TABLE t_test

(

    id integer,

    name text COLLATE pg_catalog."default",

    address character varying(500) COLLATE pg_catalog."default"

);

插入测试数据

insert into t_test SELECT generate_series(1,10000000) as key, ‘name‘||(random()*(10^3))::integer, ‘ChangAn Street NO‘||(random()*(10^3))::integer;

建立3列索引

create index idx_t_test_id_name_address on t_test(id,name,address);

1.以下查询语句可以使用索引且较快

索引第一列在where语句，与条件次序无关

一般3毫秒多出结果

explain analyze select * from t_test where id < 2000 and name like ‘name%‘ and address like ‘ChangAn%‘;

explain analyze select * from t_test where address like ‘ChangAn%‘ and name like ‘name%‘ and id < 2000 ;

explain analyze select * from t_test where name like ‘name%‘ and id < 2000 and address like ‘ChangAn%‘  ;

explain analyze select * from t_test where id < 2000

explain analyze select * from t_test where  name like ‘name%‘ and id < 2000 

explain analyze select * from t_test where  address like ‘ChangAn%‘ and id < 2000 ;

explain analyze select * from t_test where address like ‘ChangAn%‘ and name like ‘name%‘ and id < 2000 ;

2.以下可以使用索引，但是查询速度较慢

索引第一列在order by 

explain analyze select * from t_test where address like ‘ChangAn%‘ and name like ‘name%‘ order by id;

17S

explain analyze select * from t_test where address like ‘ChangAn%‘ order by id;

8s

explain analyze select * from t_test where name like ‘name%‘ order by id;

9s

以下语句无法使用索引，索引第一列不在 where 或者 order by

explain analyze select * from t_test where address like ‘ChangAn%‘ and name like ‘name%‘;

explain analyze select * from t_test where address like ‘ChangAn%‘;

explain analyze select * from t_test where name like ‘name%‘;

建立双列索引

create index idx_t_test_name_address on t_test(name,address);

以下语句会使用索引

explain analyze select * from t_test where name = ‘name580‘;

explain analyze select * from t_test where address like ‘ChangAn%‘ and name like ‘name580‘; 

explain analyze select * from t_test where address like ‘ChangAn%‘ and name = ‘name580‘;

下面语句不会使用索引

explain analyze select * from t_test where name  like ‘name%‘

explain analyze select * from t_test where address like ‘ChangAn%‘

explain analyze select * from t_test where address = ‘ChangAn Street NO416‘

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