高精度加减乘除

Posted _BitterSweet

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了高精度加减乘除相关的知识,希望对你有一定的参考价值。

高精度加法

#include <iostream>
#include <vector>

using namespace std;

vector<int> add(vector<int> &A, vector<int> &B)

    if (A.size() < B.size()) return add(B, A);

    vector<int> C;
    int t = 0;
    for (int i = 0; i < A.size(); i ++ )
    
        t += A[i];
        if (i < B.size()) t += B[i];
        C.push_back(t % 10);
        t /= 10;
    

    if (t) C.push_back(t);
    return C;


int main()

    string a, b;
    vector<int> A, B;
    cin >> a >> b;
    for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');
    for (int i = b.size() - 1; i >= 0; i -- ) B.push_back(b[i] - '0');

    auto C = add(A, B);

    for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i];
    cout << endl;

    return 0;

高精度减法

#include <iostream>
#include <vector>

using namespace std;

bool cmp(vector<int> &A, vector<int> &B)

    if (A.size() != B.size()) return A.size() > B.size();

    for (int i = A.size() - 1; i >= 0; i -- )
        if (A[i] != B[i])
            return A[i] > B[i];

    return true;


vector<int> sub(vector<int> &A, vector<int> &B)

    vector<int> C;
    for (int i = 0, t = 0; i < A.size(); i ++ )
    
        t = A[i] - t;
        if (i < B.size()) t -= B[i];
        C.push_back((t + 10) % 10);
        if (t < 0) t = 1;
        else t = 0;
    

    while (C.size() > 1 && C.back() == 0) C.pop_back();
    return C;


int main()

    string a, b;
    vector<int> A, B;
    cin >> a >> b;
    for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');
    for (int i = b.size() - 1; i >= 0; i -- ) B.push_back(b[i] - '0');

    vector<int> C;

    if (cmp(A, B)) C = sub(A, B);
    else C = sub(B, A), cout << '-';

    for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i];
    cout << endl;

    return 0;

高精度乘法

#include <iostream>
#include <vector>

using namespace std;


vector<int> mul(vector<int> &A, int b)

    vector<int> C;

    int t = 0;
    for (int i = 0; i < A.size() || t; i ++ )
    
        if (i < A.size()) t += A[i] * b;
        C.push_back(t % 10);
        t /= 10;
    

    while (C.size() > 1 && C.back() == 0) C.pop_back();

    return C;



int main()

    string a;
    int b;

    cin >> a >> b;

    vector<int> A;
    for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');

    auto C = mul(A, b);

    for (int i = C.size() - 1; i >= 0; i -- ) printf("%d", C[i]);

    return 0;



高精度除法

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

vector<int> div(vector<int> &A, int b, int &r)

    vector<int> C;
    r = 0;
    for (int i = A.size() - 1; i >= 0; i -- )
    
        r = r * 10 + A[i];
        C.push_back(r / b);
        r %= b;
    
    reverse(C.begin(), C.end());
    while (C.size() > 1 && C.back() == 0) C.pop_back();
    return C;


int main()

    string a;
    vector<int> A;

    int B;
    cin >> a >> B;
    for (int i = a.size() - 1; i >= 0; i -- ) A.push_back(a[i] - '0');

    int r;
    auto C = div(A, B, r);

    for (int i = C.size() - 1; i >= 0; i -- ) cout << C[i];

    cout << endl << r << endl;

    return 0;


以上是关于高精度加减乘除的主要内容,如果未能解决你的问题,请参考以下文章

js加减法运算多出很多小数点

大数运算(加减乘除)

PHP 精准加减乘除

求助 c语言实现高精度乘法

高精度加减及混合

高精度运算(除法待完善)