oracle树形查询 start with connect by
Posted AaronBear
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一、简介
在oracle中start with connect by (prior) 用来对树形结构的数据进行查询。其中start with conditon 给出的是数据搜索范围, connect by后面给出了递归查询的条件,prior 关键字表示父数据,prior 条件表示子数据需要满足父数据的什么条件。如下
start with id= \'10001\' connect by prior parent_id= id and prior num = 5
表示查询id为10001,并且递归查询parent_id=id,为5的记录。
二、实例
1、构造数据
1 -- 表结构 2 create table menu( 3 id varchar2(64) not null, 4 parent_id varchar2(64) not null, 5 name varchar2(100) not null, 6 depth number(2) not null, 7 primary key (id) 8 ) 9 10 -- 初始化数据 11 -- 顶级菜单 12 insert into menu values (\'100000\', \'0\', \'顶级菜单1\', 1); 13 insert into menu values (\'200000\', \'0\', \'顶级菜单2\', 1); 14 insert into menu values (\'300000\', \'0\', \'顶级菜单3\', 1); 15 16 -- 父级菜单 17 -- 顶级菜单1 直接子菜单 18 insert into menu values (\'110000\', \'100000\', \'菜单11\', 2); 19 insert into menu values (\'120000\', \'100000\', \'菜单12\', 2); 20 insert into menu values (\'130000\', \'100000\', \'菜单13\', 2); 21 insert into menu values (\'140000\', \'100000\', \'菜单14\', 2); 22 -- 顶级菜单2 直接子菜单 23 insert into menu values (\'210000\', \'200000\', \'菜单21\', 2); 24 insert into menu values (\'220000\', \'200000\', \'菜单22\', 2); 25 insert into menu values (\'230000\', \'200000\', \'菜单23\', 2); 26 -- 顶级菜单3 直接子菜单 27 insert into menu values (\'310000\', \'300000\', \'菜单31\', 2); 28 29 -- 菜单13 直接子菜单 30 insert into menu values (\'131000\', \'130000\', \'菜单131\', 3); 31 insert into menu values (\'132000\', \'130000\', \'菜单132\', 3); 32 insert into menu values (\'133000\', \'130000\', \'菜单133\', 3); 33 34 -- 菜单132 直接子菜单 35 insert into menu values (\'132100\', \'132000\', \'菜单1321\', 4); 36 insert into menu values (\'132200\', \'132000\', \'菜单1332\', 4); 37
生成的菜单层次结构如下:
顶级菜单1
菜单11
菜单12
菜单13
菜单131
菜单132
菜单1321
菜单1322
菜单133
菜单14
顶级菜单2
菜单21
菜单22
菜单23
顶级菜单3
菜单31
2、SQL查询
--prior放的左右位置决定了检索是自底向上还是自顶向下. 左边是自上而下(找子节点),右边是自下而上(找父节点) --找父节点 select * from menu start with id=\'130000\' connect by id = prior parent_id;
--找子节点节点 -- (子节点)id为130000的菜单,以及130000菜单下的所有直接或间接子菜单(prior 在左边, prior、parent_id(等号右边)在右边) select * from menu start with id=\'130000\' connect by prior id = parent_id ;
-- (父节点)id为1321的菜单,以及1321菜单下的所有直接或间接父菜单(prior、parent_id(等号左边) 都在左边) select * from menu start with id=\'132100\' connect by prior parent_id = id; -- prior 后面跟的是(parent_id) 则是查找父节点,prior后面跟的是(id)则是查找子节点
--根据菜单组分类统计每个菜单包含子菜单的个数 select id, max(name) name, count(1) from menu group by id connect by prior parent_id = id order by id
-- 查询所有的叶子节点 select t2.* from menu t2 where id not in(select t.parent_id from menu t) order by id;
三、性能问题
对于 start with connect by语句的执行,oracle会进行递归查询,当数据量大的时候会产生性能相关问题。
--生成执行计划 explain plan for select * from menu start with id=\'132100\' connect by prior parent_id = id; -- 查询执行计划 select * from table( dbms_xplan.display);
语句执行计划结果如下:
Plan hash value: 3563250490 ---------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ---------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 133 | 1 (0)| 00:00:01 | |* 1 | CONNECT BY WITH FILTERING | | | | | | | 2 | TABLE ACCESS BY INDEX ROWID | MENU | 1 | 133 | 1 (0)| 00:00:01 | |* 3 | INDEX UNIQUE SCAN | SYS_C0018586 | 1 | | 1 (0)| 00:00:01 | | 4 | NESTED LOOPS | | | | | | | 5 | CONNECT BY PUMP | | | | | | | 6 | TABLE ACCESS BY INDEX ROWID| MENU | 1 | 133 | 1 (0)| 00:00:01 | |* 7 | INDEX UNIQUE SCAN | SYS_C0018586 | 1 | | 1 (0)| 00:00:01 | ---------------------------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 1 - access("ID"=PRIOR "PARENT_ID") 3 - access("ID"=\'132100\') 7 - access("ID"=PRIOR "PARENT_ID") Note ----- - dynamic sampling used for this statement
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