SQL之学生名次问题

Posted 2020-08-15 冷的锋刃

--对输入的数据进行约束
create table t(studentID char(10), [name] varchar(8),
startDate char(10) Check (isdate(startdate)=1 and cast(startdate as datetime)=convert(datetime,startdate,120)))
insert into t
select ‘aa‘,‘bb‘,‘77799820‘
union all select ‘bb‘,‘ggg‘,‘2007-10-11‘
union all select ‘cc‘,‘ddd‘,‘2007-20-11‘
select * from t
--创建测试表
create table tbl ([name] varchar(8), chinese float, math float,zong float,px int)
insert tbl
select ‘a‘, 80, 90,null,null
union all select ‘b‘, 85, 88,null,null
union all select ‘c‘, 77, 93,null,null
union all select ‘d‘, 80, 90,null,null
union all select ‘e‘, 99, 100,null,null
--另一种方法
select *,zong=chinese + math,
px=(select count(1)+1 from tbl b where b.chinese + b.math >a.chinese + a.math )
from tbl a order by px,chinese

 

--创建存储过程
create proc mysql
as
update bb set zong=tt.zong,px=tt.px from tbl bb,
(SELECT name,zong , px=(SELECT COUNT(zong) FROM
(
select name,chinese,math,zong = chinese + math from tbl
) t
WHERE zong > a.zong or (zong = a.zong and chinese > a.chinese)) + 1
FROM
(
select name,chinese,math,zong = chinese + math from tbl
) a
) tt
where bb.name=tt.name
go
--调用存储过程
exec mysql
--查看
select * from tbl

--删除
drop table tbl
drop proc mysql

--创建表
create table tb(ID int,TEAM varchar(10),SCORE int,SCORE2 int,SCORE3 int)
insert into tb values(1, ‘A ‘, 100 , 100 , 100)
insert into tb values(2, ‘A ‘, 90 , 100 , 100)
insert into tb values(3, ‘B ‘, 50 , 40 , 30 )
insert into tb values(4, ‘B ‘, 50 , 40 , 30)
insert into tb values(5, ‘A ‘, 90 , 100 , 80)
insert into tb values(6, ‘B ‘, 55 , 50 , 50)
insert into tb values(7, ‘A ‘, 90 , 100 , 50)

--查询
select *,px=(select count(1)+1 from tb
where team=a.team and (score >a.score)
or (score = a.score and score2 >a.score2)
or (score = a.score and score2=a.score2 and score3 >a.score3)
or (score = a.score and score2=a.score2 and score3=a.score3 and id <a.id))
from tb a order by team

--删除
drop table tb