Oracle考试题作业

Posted 2020-10-01 麻包缝裤衩

新建一张学员信息表(student)，要求：
1. 字段如下：学号(sid)，姓名(name)，性别(sex)，年龄(age)，地址(address)．
2. 分别为字段添加约束：学号为主键，姓名为非空，性别为检查约束，年龄为检查约束，地址为默认约束．
3. 创建序列插入学号（sid）列, 建议初始值从为1001, 增量为1.
4. 插入记录．

create table student(sid int, name char(1), sex char(2), age int, address varchar2(20));

alter table student modify sid primary key;

alter table student modify name not null;

alter table student modify sex check(sex=‘m‘ or sex=‘w‘);

alter table student modify age check(age between 10 and 100);

alter table student modify address varchar2(500) default‘20‘;

create sequence student_sid start with 1001 increment by 1;

insert into student(sid,name,sex,age,address) values(student_sid.nextval,‘1‘, ‘w‘, 16, ‘china‘);

insert into student values(student_sid.nextval, 2, ‘m‘, 18, ‘china‘); insert into student values(student_sid.nextval, 3, ‘m‘, 19, ‘china‘);

commit;

 

 

 

新建一张课程表(course)，要求：
1. 字段如下：课程编号(cid)，课程名称(subject)．
2. 分别为字段添加约束：课程编号为主键，课程名称为非空
3. 创建序列插入课程编号列(cid), 建议初始值从为1, 增量为1.
4. 插入记录．

 

create table course(cid int, subject char(20));

alter table course modify cid primary key;

alter table course modify subject not null;

create sequence course_cid start with 1 increment by 1;

insert into course values(course_cid.nextval,‘yuwen‘, ‘shuxue‘, ‘yingyu‘);

commit;

 

 

新建一张学员考试成绩表(grade)，要求：
1. 字段如下：成绩编号(gid)，学号(sid)，课程编号(cid)，考试成绩(score).
2. 分别为字段添加约束：成绩编号为主键，学号为外键，课程编号为外键，考试成绩为非空.
3. 创建序列插入成绩编号列(gid), 建议初始值从为101, 增量为1.
4. 插入记录．

create table grade(gid int, sid int, cid int, score int);

alter table grade modify gid primary key;

alter table grade add constraint fk_grade_sid foreign key(sid) references student(sid);

alter table grade add constraint fk_grade_cid foreign key(cid) references student(cid);

create sequence grade_gid start with 101 increment by 1;

insert into grade values(grade_gid.nextval,1001,1,50);

insert into grade values(grade_gid.nextval,1001,2,90);

insert into grade values(grade_gid.nextval,1001,3,80);

insert into grade values(grade_gid.nextval,1002,1,50);

insert into grade values(grade_gid.nextval,1002,2,70);

insert into grade values(grade_gid.nextval,1002,3,80);

insert into grade values(grade_gid.nextval,1003,1,50);

insert into grade values(grade_gid.nextval,1003,2,59);

insert into grade values(grade_gid.nextval,1003,3,70);

select * from grade;

commit;

 

 

针对以上三张表，要求完成如下：
1. 按照课程编号分组并求出每一组的平均分数(每门课程的平均分)
2. 按照课程编号分组并求出每一组及格人数(grade >= 60)的平均分数(每门课程的及格人数的平均分)
3. 求每个学员所有的课程的平均分
4. 求每个学员所有的（考试成绩）及格课程的平均分
5. 每次内部测试不同学员的平均成绩(每个学员的每门课程的平均分)
6. 查询补考过的学员的平均成绩(求出学员的课程编号(cid)在分组内出现过一次以上)(每个学员的每门课
程的课程编号出现过一次以上)
7. 使用多表内连接查询，求出学员的学号，姓名，考号，科目和成绩
8. 建立一张视图，包含学员的学号，姓名，考号，科目，成绩这些字段

1. select cid,avg(score) from grade group by cid;

2. select cid,avg(score) from grade where score>=60 group by cid;

3. select sid, avg(score) from grade group by sid;

4. select sid,avg(score) from grade where score>=60 group by sid;

5. select cid,sid,avg(score) from grade group by sid,cid order by sid;

6. select sid,avg(score) from grade where sid in(select sid from grade group by sid,cid having count(cid)>1) group by sid;

插入一条补考过得记录：insert into grade values（grade_gid.nextval，1003,2,70）；

7.Select s.sid ,s.name,g.gid,c.cid,g.score
form student s,course c,grade g
where s.sid=g.sid
and c.cid=g.cid;

 

8. create or replace view score as
Select s.sid, s.name, g.gid, c.cid, g.score
from student s, course c, grade g
where s.sid=g.sid and c.cid=g.cid;