Linux操作系统下oracle数据库中不存在scott用户的解决方案

Posted 2020-09-30

① 以‘sys‘用户登录到数据库中，输入select * from dba_users;查看一下是否存在scott用户，如下图所示：

如上图所示，scott用户的确不存在。

② 由于操作系统是Linux，则用xshell登录Linux界面，切换到oracle用户，如下图所示，找到如下目录，看是否存在scott.sql文件：

/home/oracle/product/ora11g/rdbms/admin -- 该路径视自己的实际路径为准 

如果存在，则以sys用户登录数据库，并执行如下语句：

如果不存在，则在/home/oracle/product/ora11g/rdbms/admin下创建scott.sql文件，并保存如下代码：

Rem Copyright (c) 1990 by Oracle Corporation

Rem NAME

REM    UTLSAMPL.SQL

Rem  FUNCTION

Rem  NOTES

Rem  MODIFIED

Rem gdudey   06/28/95 -  Modified for desktop seed database

Rem glumpkin   10/21/92 -  Renamed from SQLBLD.SQL

Rem blinden   07/27/92 -  Added primary and foreign keys to EMP and DEPT

Rem rlim   04/29/91 -      change char to varchar2

Rem mmoore   04/08/91 -      use unlimited tablespace priv

Rem pritto   04/04/91 -      change SYSDATE to 13-JUL-87

Rem   Mendels 12/07/90 - bug 30123;add to_date calls so language independent

Rem

rem

rem $Header: utlsampl.sql 7020100.1 94/09/23 22:14:24 cli Generic<base> $ sqlbld.sql

rem

SET TERMOUT OFF

SET ECHO OFF

 

rem CONGDON    Invoked in RDBMS at build time. 29-DEC-1988

rem OATES:     Created: 16-Feb-83

 

GRANT CONNECT,RESOURCE,UNLIMITED TABLESPACE TO SCOTT IDENTIFIED BY TIGER;

ALTER USER SCOTT DEFAULT TABLESPACE USERS;

ALTER USER SCOTT TEMPORARY TABLESPACE TEMP;

CONNECT SCOTT/TIGER

DROP TABLE DEPT;

CREATE TABLE DEPT

       (DEPTNO NUMBER(2) CONSTRAINT PK_DEPT PRIMARY KEY,

DNAME VARCHAR2(14) ,

LOC VARCHAR2(13) ) ;

DROP TABLE EMP;

CREATE TABLE EMP

       (EMPNO NUMBER(4) CONSTRAINT PK_EMP PRIMARY KEY,

ENAME VARCHAR2(10),

JOB VARCHAR2(9),

MGR NUMBER(4),

HIREDATE DATE,

SAL NUMBER(7,2),

COMM NUMBER(7,2),

DEPTNO NUMBER(2) CONSTRAINT FK_DEPTNO REFERENCES DEPT);

INSERT INTO DEPT VALUES

(10,‘ACCOUNTING‘,‘NEW YORK‘);

INSERT INTO DEPT VALUES (20,‘RESEARCH‘,‘DALLAS‘);

INSERT INTO DEPT VALUES

(30,‘SALES‘,‘CHICAGO‘);

INSERT INTO DEPT VALUES

(40,‘OPERATIONS‘,‘BOSTON‘);

INSERT INTO EMP VALUES

(7369,‘SMITH‘,‘CLERK‘,7902,to_date(‘17-12-1980‘,‘dd-mm-yyyy‘),800,NULL,20);

INSERT INTO EMP VALUES

(7499,‘ALLEN‘,‘SALESMAN‘,7698,to_date(‘20-2-1981‘,‘dd-mm-yyyy‘),1600,300,30);

INSERT INTO EMP VALUES

(7521,‘WARD‘,‘SALESMAN‘,7698,to_date(‘22-2-1981‘,‘dd-mm-yyyy‘),1250,500,30);

INSERT INTO EMP VALUES

(7566,‘JONES‘,‘MANAGER‘,7839,to_date(‘2-4-1981‘,‘dd-mm-yyyy‘),2975,NULL,20);

INSERT INTO EMP VALUES

(7654,‘MARTIN‘,‘SALESMAN‘,7698,to_date(‘28-9-1981‘,‘dd-mm-yyyy‘),1250,1400,30);

INSERT INTO EMP VALUES

(7698,‘BLAKE‘,‘MANAGER‘,7839,to_date(‘1-5-1981‘,‘dd-mm-yyyy‘),2850,NULL,30);

INSERT INTO EMP VALUES

(7782,‘CLARK‘,‘MANAGER‘,7839,to_date(‘9-6-1981‘,‘dd-mm-yyyy‘),2450,NULL,10);

INSERT INTO EMP VALUES

(7788,‘SCOTT‘,‘ANALYST‘,7566,to_date(‘13-JUL-87‘)-85,3000,NULL,20);

INSERT INTO EMP VALUES

(7839,‘KING‘,‘PRESIDENT‘,NULL,to_date(‘17-11-1981‘,‘dd-mm-yyyy‘),5000,NULL,10);

INSERT INTO EMP VALUES

(7844,‘TURNER‘,‘SALESMAN‘,7698,to_date(‘8-9-1981‘,‘dd-mm-yyyy‘),1500,0,30);

INSERT INTO EMP VALUES

(7876,‘ADAMS‘,‘CLERK‘,7788,to_date(‘13-JUL-87‘)-51,1100,NULL,20);

INSERT INTO EMP VALUES

(7900,‘JAMES‘,‘CLERK‘,7698,to_date(‘3-12-1981‘,‘dd-mm-yyyy‘),950,NULL,30);

INSERT INTO EMP VALUES

(7902,‘FORD‘,‘ANALYST‘,7566,to_date(‘3-12-1981‘,‘dd-mm-yyyy‘),3000,NULL,20);

INSERT INTO EMP VALUES

(7934,‘MILLER‘,‘CLERK‘,7782,to_date(‘23-1-1982‘,‘dd-mm-yyyy‘),1300,NULL,10);

DROP TABLE BONUS;

CREATE TABLE BONUS

(

ENAME VARCHAR2(10) ,

JOB VARCHAR2(9)  ,

SAL NUMBER,

COMM NUMBER

) ;

DROP TABLE SALGRADE;

CREATE TABLE SALGRADE

      ( GRADE NUMBER,

LOSAL NUMBER,

HISAL NUMBER );

INSERT INTO SALGRADE VALUES (1,700,1200);

INSERT INTO SALGRADE VALUES (2,1201,1400);

INSERT INTO SALGRADE VALUES (3,1401,2000);

INSERT INTO SALGRADE VALUES (4,2001,3000);

INSERT INTO SALGRADE VALUES (5,3001,9999);

COMMIT;

 

SET TERMOUT ON

SET ECHO ON

然后再执行：

即可。

到此，scott添加成功。

如果需要修改scott用户密码，则执行如下语句：

alter user scott identified by 123456;

怎么样？是不是很简单呢？

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