oracle计算时间秒数差

Posted 2020-08-15 秦正全

--计算plsql处理时间差
--qzq

declare
  time1 timestamp;      --开始时间
  time2 timestamp;    --结束时间
  sum1 number(9);    --时间差(s)
begin
  time1 := to_timestamp(to_char(sysdate,‘yyyy-mm-dd hh24-mi-ss‘),‘yyyy-mm-dd hh24:mi:ss.ff9‘);

  --处理任务
  for i in 1..600000 loop 
       select 1 into sum1 from dual;
  end loop;

  time2 := to_timestamp(to_char(sysdate,‘yyyy-mm-dd hh24-mi-ss‘),‘yyyy-mm-dd hh24:mi:ss.ff9‘);
 
  sum1 := abs((trunc(time1 - 0, ‘mi‘) - trunc((time2 - 0), ‘mi‘)) * 24 * 60 * 60 + extract(second from time1 - time2));  
  
  dbms_output.put_line(sum1||‘s‘);

end;