MySQL中group_concat函数
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完整的语法如下:
group_concat([DISTINCT] 要连接的字段 [Order BY ASC/DESC 排序字段] [Separator ‘分隔符‘])
基本查询
- select * from aa;
+------+------+
| id| name |
+------+------+
|1 | 10|
|1 | 20|
|1 | 20|
|2 | 20|
|3 | 200 |
|3 | 500 |
+------+------+
6 rows in set (0.00 sec)
以id分组,把name字段的值打印在一行,逗号分隔(默认)
- select id,group_concat(name) from aa group by id;
+------+--------------------+
| id| group_concat(name) |
+------+--------------------+
|1 | 10,20,20|
|2 | 20 |
|3 | 200,500|
+------+--------------------+
3 rows in set (0.00 sec)
以id分组,把name字段的值打印在一行,分号分隔
- select id,group_concat(name separator ‘;‘) from aa group by id;
+------+----------------------------------+
| id| group_concat(name separator ‘;‘) |
+------+----------------------------------+
|1 | 10;20;20 |
|2 | 20|
|3 | 200;500 |
+------+----------------------------------+
3 rows in set (0.00 sec)
以id分组,把去冗余的name字段的值打印在一行,
逗号分隔
- select id,group_concat(distinct name) from aa group by id;
+------+-----------------------------+
| id| group_concat(distinct name) |
+------+-----------------------------+
|1 | 10,20|
|2 | 20 |
|3 | 200,500 |
+------+-----------------------------+
3 rows in set (0.00 sec)
以id分组,把name字段的值打印在一行,逗号分隔,以name排倒序
- select id,group_concat(name order by name desc) from aa group by id;
+------+---------------------------------------+
| id| group_concat(name order by name desc) |
+------+---------------------------------------+
|1 | 20,20,10 |
|2 | 20|
|3 | 500,200|
+------+---------------------------------------+
3 rows in set (0.00 sec)
测试sql,项目中用到的。
- SELECT
- EMPLOYEES.EMPID
- ,EMPLOYEES.EMPNAME
- ,DEPARTMENTS.DEPARTMENTNAME
- ,EMPLOYEES.DEPTID
- ,EMPLOYEES.EMPPWD
- ,EMPLOYEES.INSIDEEMAIL
- ,EMPLOYEES.OUTSIDEEMAIL
- ,EMPLOYEES.DELEFLAG
- ,EMPLOYEES.EMPCLASS
- ,(CONCAT(‘[‘, <span style="color: #ff0000;">GROUP_CONCAT</span>
- (ROLE.Role_Name SEPARATOR ‘],[‘), ‘]‘)) AS ROLENAME
- ,(concat( ‘[‘, (
- SELECT
- <span style="color: #ff0000;">GROUP_CONCAT</span>
- (DEPARTMENTS.DEPARTMENTNAME separator ‘],[‘)
- FROM
- EMP_ROLE_DEPT
- LEFT JOIN DEPARTMENTS
- ON (
- DEPARTMENTS.DEPARTMENTID = EMP_ROLE_DEPT.DEPTID
- AND DEPARTMENTS.DELEFLAG = 0
- )
- GROUP BY
- EMP_ROLE_DEPT.EMPID
- HAVING
- EMP_ROLE_DEPT.EMPID = EMPLOYEES.EMPID
- ),‘]‘)) AS DEPARTMENTRIGHT
- FROM
- EMPLOYEES
- LEFT JOIN DEPARTMENTS
- ON (
- DEPARTMENTS.DEPARTMENTID = EMPLOYEES.DEPTID
- AND DEPARTMENTS.DELEFLAG = 0
- )
- LEFT JOIN ROLE_EMP
- ON (ROLE_EMP.EMP_ID = EMPLOYEES.EMPID)
- LEFT JOIN ROLE
- ON (ROLE_EMP.ROLE_ID = ROLE.ROLE_ID)
- <span style="color: #ff0000;"> GROUP BY
- EMPLOYEES.EMPID</span>
- HAVING
- EMPLOYEES.EMPID LIKE ‘%%‘
- AND EMPLOYEES.EMPNAME LIKE ‘%%‘
- AND EMPLOYEES.DELEFLAG = 0
- AND (
- EMPLOYEES.EMPCLASS = ‘1‘
- OR EMPLOYEES.EMPCLASS = ‘2‘
- )
- AND EMPLOYEES.DEPTID = ‘001‘ LIMIT 0
- ,16
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