SqlServer 中查询子节对应的上级自定义函数

Posted 2020-09-20 石

CREATE FUNCTION [dbo].[FN_TopGetOrgByUserName]
(	
		@UserName NVARCHAR(128)
)
RETURNS @showOrg TABLE(id NVARCHAR(36)) 
AS
BEGIN
	DECLARE @baseOrg TABLE(id NVARCHAR(36),
	fullpath  NVARCHAR(200),
	shortName  NVARCHAR(200),
	parentid  NVARCHAR(36),
	[level] INT,index_baseOrg INT)

	INSERT INTO @baseOrg
	SELECT id,fullpath,shortName,parentid,[level],ROW_NUMBER()OVER(ORDER BY id)  FROM SysOrganization 
	WHERE id IN (
	SELECT OrgID FROM SysPosition ,SysUserPosition,SysUser
	WHERE SysPosition.ID=SysPosition  AND SysUser.ID=SysUser_ID
	AND [email protected]
	AND basepositionid=‘‘
	)
	AND IsEnable=1 AND (IsDel=0 OR IsDel IS NULL)

	DECLARE @i INT
	DECLARE @j INT
	SET @i=1
	SELECT @j=COUNT(*)FROM @baseOrg WHERE [level]=1
	IF @j=1
	BEGIN 
		INSERT INTO @showOrg
		SELECT id FROM SysOrganization
		WHERE  IsEnable=1 AND( IsDel=0 OR isdel IS NULL )
		
			END
	ELSE
		BEGIN
		SELECT @j=COUNT(*)FROM @baseOrg
		WHILE @i<[email protected]
		BEGIN
			DECLARE @currentID NVARCHAR(36)
			SELECT @currentID=ID FROM @baseOrg WHERE [email protected]
			DECLARE @levelChild INT 
			DECLARE @t_level TABLE(id VARCHAR(MAX) , [level] INT) 
			SET @levelChild = 1 
			INSERT @t_level SELECT @currentID, @levelChild 
			WHILE @@ROWCOUNT > 0 
				BEGIN 
					SET @levelChild = @levelChild + 1 
					INSERT INTO @t_level SELECT a.ID , @levelChild 
					FROM SysOrganization a , @t_Level b 
					WHERE a.ParentID = b.id AND b.[level] = @levelChild - 1 
				END 
			INSERT INTO @showOrg SELECT id FROM @t_level WHERE id NOT IN (SELECT id FROM @showOrg)
			SET @[email protected]+1
		END
	END
RETURN 
END

GO

 Split 表函数将一个字符串按指定分隔符进行分割，返回一个表。  charindex：在一段字符中搜索字符或者字符串

create function split(  
    @string varchar(255),--待分割字符串  
    @separator varchar(255)--分割符  
)returns @array table(item varchar(255))  
as  
begin  
    declare @begin int,@end int,@item varchar(255)  
    set @begin = 1  
    set @end=charindex(@separator,@string,@begin)  
    while(@end<>0)  
    begin  
        set @item = substring(@string,@begin,@[email protected])  
        insert into @array(item) values(@item)  
        set @begin = @end+1  
        set @end=charindex(@separator,@string,@begin)  
    end  
    set @item = substring(@string,@begin,len(@string)[email protected])  
    if (len(@item)>0)  
        insert into @array(item) values(substring(@string,@begin,len(@string)[email protected]))  
    return  
end