oracle 组函数
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完整的select ** from ** where ** group by ** having ** order by **;
select job_id,sum(salary) payroll from employees where job_id not like \'%REP%\' group by job_id having sum(salary)>1300 order by sum(salary)
group by的增强 SQL> select deptno,job,sum(sal) from emp group by deptno,job SQL> + SQL> select deptno,sum(sal) from emp group by deptno SQL> + SQL> select sum(sal) from emp SQL> SQL> === SQL> SQL> select deptno,job,sum(sal) from emp group by rollup(deptno,job); SQL> SQL> 抽象 SQL> group by rollup(a,b) SQL> == SQL> group by a,b SQL> + SQL> group by a SQL> + SQL> group by null SQL> SQL> */ SQL> select deptno,job,sum(sal) from emp group by rollup(deptno,job);
报表
break on deptno skip 2
SQL> /
DEPTNO JOB SUM(SAL)
---------- --------- ----------
10 CLERK 1300
MANAGER 2450
PRESIDENT 5000
8750
20 CLERK 1900
ANALYST 6000
MANAGER 2975
10875
DEPTNO JOB SUM(SAL)
---------- --------- ----------
30 CLERK 950
MANAGER 2850
SALESMAN 5600
9400
29025
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