C语言实现x的n次方

Posted 2022-12-12 a1314521531

C语言实现x的n次方

   

#include <stdio.h> //  codeblock编辑和编译的

#define uint8_t  unsigned char
#define uint32_t unsigned int
#define POWER 16

// 求x的n次方，返回x的n次方的值
uint32_t Power(uint8_t x, uint8_t n)

  uint8_t i;
  uint32_t val = 1;

  for(i = 0; i <= n; ++i)
  
    printf("%d^%d\\t%d\\n", x, i, val);
    val = x * val;
  

  return val / x;


int main(void)

  uint32_t sum;

  sum = Power(3, 16); // 3,16随便换，0~255
  printf("---%d---\\n", sum);

  return 0;