禁止在EditText中输入表情及表情符号的方法

Posted 2022-12-11 zjzjt

//匹配非表情符号的正则表达式
 private final String reg ="^([a-z]|[A-Z]|[0-9]|[\\u2E80-\\u9FFF])3,|@(?:[\\\\w](?:[\\\\w-]*[\\\\w])?\\\\.)+[\\\\w](?:[\\\\w-]*[\\\\w])?|[wap.]4|[www.]4|[blog.]5|[bbs.]4|[.com]4|[.cn]3|[.net]4|[.org]4|[http://]7|[ftp://]6$";  

private Pattern pattern = Pattern.compile(reg);
 //输入表情前的光标位置
 private int cursorPos;
 //输入表情前EditText中的文本
 private String tmp;
 //是否重置了EditText的内容
 private boolean resetText;
 private TextWatcher watcher = new TextWatcher() 

  @Override
  public void onTextChanged(CharSequence s, int start, int before, int count) 
   if(!resetText)
    if(count >= 3)//表情符号的字符长度最小为3
     //提取输入的长度大于3的文本
     CharSequence input = s.subSequence(cursorPos, cursorPos + count);
     //正则匹配是否是表情符号
     Matcher matcher = pattern.matcher(input.toString());
     if(!matcher.matches())
      resetText = true;
      //是表情符号就将文本还原为输入表情符号之前的内容
      contentEd.setText(tmp);
      contentEd.invalidate();
      Toast.makeText(ShareInstantActivity.this,
        "不支持表情输入", Toast.LENGTH_SHORT).show();
      
    
   else
    resetText = false;
   
  

  @Override
  public void beforeTextChanged(CharSequence s, int start, int count, int after) 
   if(!resetText)
    cursorPos = contentEd.getSelectionEnd();
    tmp = s.toString();//这里用s.toString()而不直接用s是因为如果用s，那么，tmp和s在内存中指向的是同一个地址，s改变了，tmp也就改变了，那么表情过滤就失败了
   

  

  @Override
  public void afterTextChanged(Editable s) 
   
 ;