C++栈和递归实验

Posted 2022-12-10 康小庄

1. 利用栈的存储原理，补充完成数制转换程序

运行结果如图所示：

完整代码

#define _CRT_SECURE_NO_WARNINGS

#include"stdio.h" 
#include"stdlib.h"
#define null 0 
#define n 10 
struct stack 
    int* base;
    int* top;
    int stacksize;
;

void initstack(struct stack* s)

    s->base = (int*)malloc(20 * sizeof(int));

    if (!s) exit(0);
    s->top = s->base;
    s->stacksize = 20;
    return;


void push(struct stack* s, int e)

    if (s->top - s->base >= s->stacksize)
    
        s->base = (int*)realloc(s->base, (s->stacksize + n) * sizeof(int));
        if (!s->base) exit(0);
        s->top = s->base + s->stacksize;
        s->stacksize += n;
    
    *(s->top)++ = e;
    return;


void pop(struct stack* s)

    int e;
    if (s->top == s->base)    return;
    e = *--s->top; printf("%d", e);
    return;


int StackEmpty(struct stack* s)


    if (s->top == s->base)   return 1;
    else    return  0;



void conversion(int N)   //10进制转换成2进制

    stack s;
    initstack(&s);
    do push(&s, N & 1);
    while (N >>= 1);
    while (!StackEmpty(&s))
        pop(&s);

int main()
    int x;
    printf("\\n请输入一个十进制数据:");
    scanf("%d", &x);
    printf("\\n 转换成二进制为: ", x);
    conversion(x);
    printf("\\n");

运行截图

2. 实现汉诺塔算法

运行结果如图所示：

完整代码

#define _CRT_SECURE_NO_WARNINGS

#include"stdio.h" 
#include"stdlib.h"
void move(char x,int n,char y)

	printf("第 %d 个  %c-->%c\\n",n,x,y);

void hanoi(int n,char x,char y,char z)

	if (n == 1)move(x, 1, y);
	else 
	
		hanoi(n - 1, x, z, y);
		move(x, n, z);
		hanoi(n - 1, y, x, z);
	





int main()

	int m;
	printf("请输入方块数目:");
	scanf("%d",&m);
	hanoi(m,'X','Y','Z');

运行截图

3. 写一个程序将读入的一个以“@”为结束符的字符序列逆序输出，如输入“asdf@”，则输出“fdsa”。要求使用栈结构完成。

运行结果如图所示：

完整代码

#define _CRT_SECURE_NO_WARNINGS

#include"stdio.h" 
#include"stdlib.h"
#define null 0 
#define n 10 
struct stack 
    int* base;
    int* top;
    int stacksize;
;

void initstack(struct stack* s)

    s->base = (int*)malloc(20 * sizeof(int));

    if (!s) exit(0);
    s->top = s->base;
    s->stacksize = 20;
    return;


void push(struct stack* s, int e)

    if (s->top - s->base >= s->stacksize)
    
        s->base = (int*)realloc(s->base, (s->stacksize + n) * sizeof(int));
        if (!s->base) exit(0);
        s->top = s->base + s->stacksize;
        s->stacksize += n;
    
    *(s->top)++ = e;
    return;


void pop(struct stack* s)

    int e;
    if (s->top == s->base)    return;
    e = *--s->top; printf("%d", e);
    return;


int StackEmpty(struct stack* s)


    if (s->top == s->base)   return 1;
    else    return  0;





void conversion(int N)   //10进制转换成2进制

    stack s;
    initstack(&s);
    do push(&s, N & 1);
    while (N >>= 1);
    while (!StackEmpty(&s))
        pop(&s);




int main()

    int x;
    printf("\\n请输入一个十进制数据:");
    scanf("%d", &x);
    printf("\\n 转换成二进制为: ", x);
    conversion(x);
    printf("\\n");





```cpp
#include <stack>
#include <iostream>
#include <string>

using std::cout;
using std::cin;
using std::endl;
using std::string;

const int MAX_SIZE = 100;

struct Stack

	char* base; char* top; int stacksize;
	Stack()  InitStack(MAX_SIZE);
	Stack(int i)  InitStack(i); 
	void InitStack(int);
	bool Push(char const& elem);
	bool Pop();
	bool Empty();
	char& GetTop();
	~Stack()  delete base; 
;

void Stack::InitStack(int i)

	base = new char[i];
	top = base;
	stacksize = i;


bool Stack::Push(char const& elem)

	if (top - base == stacksize)
		return false;
	*top++ = elem;
	return true;


bool Stack::Pop()

	if (top == base)
		return false;
	--top;
	return true;


char& Stack::GetTop()

	if (top != base)
		return *(top - 1);


bool Stack::Empty()

	if (top == base)   return true;
	else    return  false;


void reverse(string& s);

int main()

	string s;
	cin >> s;
	if (s.back() == '\\@')
		reverse(s);
	cout << s << endl;


void reverse(string& s) 

	Stack stack;
	for (int i = 0; i < s.length() - 1; i++)
	
		stack.Push(s[i]);
	
	s = "";
	while (!stack.Empty()) 
	
		s += stack.GetTop();
		stack.Pop();
	

运行截图