R语言 数据帧

Posted 方舟编译器开源

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了R语言 数据帧相关的知识,希望对你有一定的参考价值。

数据帧是表或二维阵列状结构,其中每一列包含一个变量的值,并且每一行包含来自每一列的一组值。
以下是数据帧的特性。


  • 列名称应为非空。

  • 行名称应该是唯一的。

  • 存储在数据帧中的数据可以是数字,因子或字符类型。

  • 每个列应包含相同数量的数据项。

创建数据帧

# Create the data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25),  start_date = as.Date(c("2012-01-01", "2013-09-23", "2014-11-15", "2014-05-11", "2015-03-27")), stringsAsFactors = FALSE)# Print the data frame.print(emp.data) 



当我们执行上面的代码,它产生以下结果 -

 emp_id emp_name salary start_date1 1 Rick 623.30 2012-01-012 2 Dan 515.20 2013-09-233 3 Michelle 611.00 2014-11-154 4 Ryan 729.00 2014-05-115 5 Gary 843.25 2015-03-27



获取数据帧的结构

通过使用str()函数可以看到数据帧的结构。

# Create the data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25),  start_date = as.Date(c("2012-01-01", "2013-09-23", "2014-11-15", "2014-05-11", "2015-03-27")), stringsAsFactors = FALSE)# Get the structure of the data frame.str(emp.data)



当我们执行上面的代码,它产生以下结果 -

'data.frame': 5 obs. of 4 variables: $ emp_id : int 1 2 3 4 5 $ emp_name : chr "Rick" "Dan" "Michelle" "Ryan" ... $ salary : num 623 515 611 729 843 $ start_date: Date, format: "2012-01-01" "2013-09-23" "2014-11-15" "2014-05-11" ...



数据框中的数据摘要

可以通过应用summary()函数获取数据的统计摘要和性质。

# Create the data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25),  start_date = as.Date(c("2012-01-01", "2013-09-23", "2014-11-15", "2014-05-11", "2015-03-27")), stringsAsFactors = FALSE)# Print the summary.print(summary(emp.data)) 



当我们执行上面的代码,它产生以下结果 -

 emp_id emp_name salary start_date Min. :1 Length:5 Min. :515.2 Min. :2012-01-01 1st Qu.:2 Class :character 1st Qu.:611.0 1st Qu.:2013-09-23 Median :3 Mode :character Median :623.3 Median :2014-05-11 Mean :3 Mean :664.4 Mean :2014-01-14 3rd Qu.:4 3rd Qu.:729.0 3rd Qu.:2014-11-15 Max. :5 Max. :843.2 Max. :2015-03-27 



从数据帧提取数据

使用列名称从数据框中提取特定列。

# Create the data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25),  start_date = as.Date(c("2012-01-01","2013-09-23","2014-11-15","2014-05-11", "2015-03-27")), stringsAsFactors = FALSE)# Extract Specific columns.result <- data.frame(emp.data$emp_name,emp.data$salary)print(result)



当我们执行上面的代码,它产生以下结果 -

 emp.data.emp_name emp.data.salary1 Rick 623.302 Dan 515.203 Michelle 611.004 Ryan 729.005 Gary 843.25



先提取前两行,然后提取所有列

# Create the data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25),  start_date = as.Date(c("2012-01-01", "2013-09-23", "2014-11-15", "2014-05-11", "2015-03-27")), stringsAsFactors = FALSE)# Extract first two rows.result <- emp.data[1:2,]print(result)



当我们执行上面的代码,它产生以下结果 -

 emp_id emp_name salary start_date1 1 Rick 623.3 2012-01-012 2 Dan 515.2 2013-09-23



用第2和第4列提取第3和第5行

# Create the data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25),  start_date = as.Date(c("2012-01-01", "2013-09-23", "2014-11-15", "2014-05-11", "2015-03-27")), stringsAsFactors = FALSE)
# Extract 3rd and 5th row with 2nd and 4th column.result <- emp.data[c(3,5),c(2,4)]print(result)



当我们执行上面的代码,它产生以下结果 -

 emp_name start_date3 Michelle 2014-11-155 Gary 2015-03-27



扩展数据帧

可以通过添加列和行来扩展数据帧。

添加列

只需使用新的列名称添加列向量。

# Create the data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25),  start_date = as.Date(c("2012-01-01", "2013-09-23", "2014-11-15", "2014-05-11", "2015-03-27")), stringsAsFactors = FALSE)
# Add the "dept" coulmn.emp.data$dept <- c("IT","Operations","IT","HR","Finance")v <- emp.dataprint(v)



当我们执行上面的代码,它产生以下结果 -

 emp_id emp_name salary start_date dept1 1 Rick 623.30 2012-01-01 IT2 2 Dan 515.20 2013-09-23 Operations3 3 Michelle 611.00 2014-11-15 IT4 4 Ryan 729.00 2014-05-11 HR5 5 Gary 843.25 2015-03-27 Finance



添加行


要将更多行永久添加到现有数据帧,我们需要引入与现有数据帧相同结构的新行,并使用rbind()函数。
在下面的示例中,我们创建一个包含新行的数据帧,并将其与现有数据帧合并以创建最终数据帧。



# Create the first data frame.emp.data <- data.frame( emp_id = c (1:5), emp_name = c("Rick","Dan","Michelle","Ryan","Gary"), salary = c(623.3,515.2,611.0,729.0,843.25), start_date = as.Date(c("2012-01-01", "2013-09-23", "2014-11-15", "2014-05-11", "2015-03-27")), dept = c("IT","Operations","IT","HR","Finance"), stringsAsFactors = FALSE)
# Create the second data frameemp.newdata <- data.frame( emp_id = c (6:8), emp_name = c("Rasmi","Pranab","Tusar"), salary = c(578.0,722.5,632.8), start_date = as.Date(c("2013-05-21","2013-07-30","2014-06-17")), dept = c("IT","Operations","Fianance"), stringsAsFactors = FALSE)
# Bind the two data frames.emp.finaldata <- rbind(emp.data,emp.newdata)print(emp.finaldata)



当我们执行上面的代码,它产生以下结果 -

 emp_id emp_name salary start_date dept1 1 Rick 623.30 2012-01-01 IT2 2 Dan 515.20 2013-09-23 Operations3 3 Michelle 611.00 2014-11-15 IT4 4 Ryan 729.00 2014-05-11 HR5 5 Gary 843.25 2015-03-27 Finance6 6 Rasmi 578.00 2013-05-21 IT7 7 Pranab 722.50 2013-07-30 Operations8 8 Tusar 632.80 2014-06-17 Fianance



以上是关于R语言 数据帧的主要内容,如果未能解决你的问题,请参考以下文章

R类型5 R语言 数据帧

R语言数据类型numeric

帧缓冲纹理出现白色(片段着色器不影响它)

网络技术理论:包片段帧数据报和段

如何根据 R 中的另一个数据帧解码一个数据帧中变量的值?

网络技术理论:包片段帧数据报和段