SQL怎么合并表?
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表一表二表三合并起来 成为表四的效果,怎么弄?如图
用SQL语句写
select * into 新表名 from (select * from T1 union all select * from T2)
这个语句可以实现将合并的数据追加到一个新表中。
不合并重复数据 select * from T1 union all select * from T2
合并重复数据 select * from T1 union select * from T2
两个表,表1 表2
如果要将 表1的数据并入表2用以下语句即可
insert into 表2(字段1,字段2) select 字段1,字段2 from b1
注意,必须把字段名全部写清楚,而且不允许把自动编号进去写进去,要合并自动编号字段必须重写一个算法一条一条记录地加进去
1 insert into b1 select * from b2
2 select * into newtable from (select * from b1 union all select * from b2)
参考技术A
2个 left join 就搞定。
sql sqlserver合并表演示
MERGE into dbo.water_quality_data_his AS target
USING dbo.water_quality_data_his_temp AS source
ON (target.id = source.id)
WHEN MATCHED
THEN UPDATE SET
target.[id] = source.[id],
target.[point_id] = source.[point_id],
target.[item_id] = source.[item_id],
target.[item_name] = source.[item_name],
target.[item_unit] = source.[item_unit],
target.[value] = source.[value],
target.[moni_time] = source.[moni_time],
target.[flag] = source.[flag],
target.[lower_limit] = source.[lower_limit],
target.[upper_limit] = source.[upper_limit],
target.[dec] = source.[dec],
target.[update_time] = source.[update_time]
when not matched by target
then insert
values(
source.[id],
source.[point_id],
source.[item_id],
source.[item_name],
source.[item_unit],
source.[value],
source.[moni_time],
source.[flag],
source.[lower_limit],
source.[upper_limit],
source.[dec],
source.[update_time]
);
--when not matched by source
-- then delete
--OUTPUT $action, Inserted.*, Deleted.*;
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