java 计算中间值

Posted 2023-05-07

如何用java编写10到20的中间值？

参考技术A import java.util.Random;

public class JavaMiddle

/**
* @param args
*/
public static void main(String[] args)
Random rand=new Random();
double middleValue=(rand.nextDouble()+1)*10;
System.out.println("Value is between 10 and 20 :\n"+middleValue);




10和20之间的数字 ....中间值....

祝楼主早日成功!本回答被提问者采纳 参考技术B public class Test

public static void main(String[] args)


double rand=Math.random()*10+10;
System.out.println(rand);




good luck to you! 参考技术C import java.util.Random；
public class Test

public static void main(String[] args)

double num=Random()*10+10;
System.out.println(num);

拼字符串成为时间，和两个计算时间点的中间值

拼字符串成为时间，和两个计算时间点的中间值

select convert(datetime,‘2016-09-18 ‘+SUBSTRING(CONVERT(varchar(100),d_bdate, 24), 0, 9),21) from B2C_daima where d_no=‘B04‘

select
case when Datename(hour,d_edate)> Datename(hour,d_bdate) then
convert(datetime,‘2016-09-19 ‘+SUBSTRING(CONVERT(varchar(100),d_edate, 24), 0, 9),21)
else
convert(datetime,‘2016-09-18 ‘+SUBSTRING(CONVERT(varchar(100),d_edate, 24), 0, 9),21) end
from B2C_daima where d_no=‘B04‘

select DateAdd(MINUTE,DATEDIFF(MINUTE,t.shangban,t.xiaban)/2 ,t.shangban) as middletime from ( select convert(datetime,‘2016-09-18 ‘+SUBSTRING(CONVERT(varchar(100),d_bdate, 24), 0, 9),21) as shangban,case when Datename(hour,d_edate)> Datename(hour,d_bdate) then
convert(datetime,‘2016-09-19 ‘+SUBSTRING(CONVERT(varchar(100),d_edate, 24), 0, 9),21)
else
convert(datetime,‘2016-09-18 ‘+SUBSTRING(CONVERT(varchar(100),d_edate, 24), 0, 9),21) end as xiaban from B2C_daima where d_no=‘B04‘ ) t