Android 使用GPS获取地理位置

Posted 2023-02-22

参考技术A ```java

//获取位置信息的入口级类，要获取位置信息，首先需要获取一个LocationManger对象

LocationManager lm = (LocationManager) getSystemService(Context.LOCATION_SERVICE);

if (!lm.isProviderEnabled(LocationManager.GPS_PROVIDER))

Toast.makeText(activity_haitao_address.this,"请手机GPS定位服务！",Toast.LENGTH_LONG).show();

return;



if (ContextCompat.checkSelfPermission(activity_haitao_address.this, Manifest.permission.ACCESS_FINE_LOCATION)

!= PackageManager.PERMISSION_GRANTED)

Toast.makeText(activity_haitao_address.this,"请授予位置信息权限！",Toast.LENGTH_LONG).show();

return;



@SuppressLint("MissingPermission") Location location = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);

if (location ==null)

Toast.makeText(activity_haitao_address.this,"获取位置失败！",Toast.LENGTH_LONG).show();

return;



double latitude = location.getLatitude();

double longitude = location.getLongitude();

v_area.setText("纬度：" + latitude +"\n" +"经度：" + longitude);

```

如何获取 Android GPS 位置

【中文标题】如何获取 Android GPS 位置

【英文标题】：How to get Android GPS location

【发布时间】：2013-05-06 02:15:03

【问题描述】：

干杯，我正在尝试通过 Android 获取当前的 GPS 位置。我也关注了this Tutorial 和Vogellas article。虽然它不起作用。使用 LocationManager.NETWORK_PROVIDER 时，无论我站在哪里，我总是得到纬度 51 度和经度度 9 度。使用 LocationManager.GPS_PROVIDER 时，我什么也得不到。

虽然使用 GMaps 时一切正常：S 不知道为什么。如何像 GMaps 一样获取当前 GPS 位置？

这是我的代码：

package com.example.gpslocation;

import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;
import android.app.Activity;
import android.content.Context;
import android.util.Log;
import android.view.Menu;

public class GPS_Location extends Activity implements LocationListener 

@Override
protected void onCreate(Bundle savedInstanceState) 
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_gps__location);

    LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0, this);


@Override
public boolean onCreateOptionsMenu(Menu menu) 
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.gps__location, menu);
    return true;


@Override
public void onLocationChanged(Location location) 
    // TODO Auto-generated method stub

    int latitude = (int) (location.getLatitude());
    int longitude = (int) (location.getLongitude());

    Log.i("Geo_Location", "Latitude: " + latitude + ", Longitude: " + longitude);


@Override
public void onProviderDisabled(String provider) 
    // TODO Auto-generated method stub



@Override
public void onProviderEnabled(String provider) 
    // TODO Auto-generated method stub



@Override
public void onStatusChanged(String provider, int status, Bundle extras) 
    // TODO Auto-generated method stub

【问题讨论】：

为了获得更高级别和更简单的 GPS 位置，您可以使用这个库：github.com/delight-im/Android-SimpleLocation

检查***.com/questions/1513485/…

【参考方案1】：

这是你的问题：

int latitude = (int) (location.getLatitude());
int longitude = (int) (location.getLongitude());

纬度和经度是double-值，因为它们以度为单位表示位置。

通过将它们转换为int，您将丢弃逗号后面的所有内容，这会产生很大的不同。见"Decimal Degrees - Wiki"

【讨论】：

已经认为这很愚蠢。你已经证明了它;P Ty

【参考方案2】：

试试看：

public LatLng getLocation()
    
     // Get the location manager
     LocationManager locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
     Criteria criteria = new Criteria();
     String bestProvider = locationManager.getBestProvider(criteria, false);
     Location location = locationManager.getLastKnownLocation(bestProvider);
     Double lat,lon;
     try 
       lat = location.getLatitude ();
       lon = location.getLongitude ();
       return new LatLng(lat, lon);
     
     catch (NullPointerException e)
         e.printStackTrace();
       return null;
     
    

【讨论】：

感谢您的回答，尽管我已经尝试过您上面的代码，只是将自己的代码剪切为最简单的解决方案来向您展示问题；P 无论如何谢谢

【参考方案3】：

这段代码有一个问题：

int latitude = (int) (location.getLatitude());
int longitude = (int) (location.getLongitude());

您可以将int 更改为double

double latitude = location.getLatitude();
double longitude = location.getLongitude();

【参考方案4】：

最初的问题是通过将lat 和lon 更改为double 来解决的。

我想用Location location = locationManager.getLastKnownLocation(bestProvider);向解决方案添加评论 它可以在其他应用程序为此进行侦听时找出最后一个已知位置。例如，如果自设备启动后没有应用程序这样做，代码将返回零（我最近花了一些时间来解决这个问题）。

另外，当locationManager.removeUpdates(this);不需要时停止收听是一个好习惯

此外，即使拥有manifest 中的权限，当在设备上的 Android 设置中启用位置服务时，该代码仍然有效。

【参考方案5】：

摘录：-

try 
        
          cnt++;scnt++;now=System.currentTimeMillis();r=rand.nextInt(6);r++;
            loc=lm.getLastKnownLocation(best);
            if(loc!=null)lat=loc.getLatitude();lng=loc.getLongitude();

            Thread.sleep(100);
            handler.sendMessage(handler.obtainMessage());
          
        catch (InterruptedException e) 
        
            Toast.makeText(this, "Error="+e.toString(), Toast.LENGTH_LONG).show();
        

正如您在上面看到的，一个线程与用户界面活动的主线程一起运行，该线程持续显示 GPS 纬度、经度以及当前时间和随机掷骰子。

如果您好奇，请查看完整代码： GPS Location with a randomized dice throw & current time in separate thread

【参考方案6】：

为这个项目工作了一天。它可能对你有用。 我压缩并组合了网络和 GPS。 MainActivity.java中直接即插即用 （显示结果有一些DIY功能）

 ///////////////////////////////////
////////// LOCATION PACK //////////
// 
//  locationManager: (LocationManager) for getting LOCATION_SERVICE
//  osLocation: (Location) getting location data via standard method
//  dataLocation: class type storage locztion data
//    x,y: (Double) Longtitude, Latitude
//  location: (dataLocation) variable contain absolute location info. Autoupdate after run locationStart();
//  AutoLocation: class help getting provider info
//  tmLocation: (Timer) for running update location over time
//  LocationStart(int interval): start getting location data with setting interval time cycle in milisecond
//  LocationStart(): LocationStart(500)
//  LocationStop(): stop getting location data
//
//  EX:
//    LocationStart(); cycleF(new Runnable() public void run()bodyM.text("LOCATION \nLatitude: " + location.y+ "\nLongitude: " + location.x).show();,500);
//

LocationManager locationManager;
Location osLocation;
public class dataLocation double x,y;
dataLocation location=new dataLocation();
public class AutoLocation extends Activity implements LocationListener 
    @Override public void onLocationChanged(Location p1)
    @Override public void onStatusChanged(String p1, int p2, Bundle p3)
    @Override public void onProviderEnabled(String p1)
    @Override public void onProviderDisabled(String p1)
    public Location getLocation(String provider) 
        if (locationManager.isProviderEnabled(provider)) 
            locationManager.requestLocationUpdates(provider,0,0,this);
            if (locationManager != null) 
                osLocation = locationManager.getLastKnownLocation(provider);
                return osLocation;
            
        
        return null;
    

Timer tmLocation=new Timer();
public void LocationStart(int interval)
    locationManager = (LocationManager) this.getSystemService(LOCATION_SERVICE);
    final AutoLocation autoLocation = new AutoLocation();
    tmLocation=cycleF(new Runnable() public void run() 
                Location nwLocation = autoLocation.getLocation(LocationManager.NETWORK_PROVIDER);
                if (nwLocation != null) 
                    location.y = nwLocation.getLatitude();
                    location.x = nwLocation.getLongitude();
                 else 
                    //bodym.text("NETWORK_LOCATION is loading...").show();
                
                Location gpsLocation = autoLocation.getLocation(LocationManager.GPS_PROVIDER);
                if (gpsLocation != null) 
                    location.y = gpsLocation.getLatitude();
                    location.x = gpsLocation.getLongitude();    
                 else 
                    //bodym.text("GPS_LOCATION is loading...").show();
                   
            , interval);

public void LocationStart()LocationStart(500);;
public void LocationStop()stopCycleF(tmLocation);

//////////
///END//// LOCATION PACK //////////
//////////


/////////////////////////////
////////// RUNTIME //////////
//
// Need library:
//  import java.util.*;
//
// delayF(r,d): execute runnable r after d millisecond
//   Halt by execute the return: final Runnable rn=delayF(...); (new Handler()).post(rn);
// cycleF(r,i): execute r repeatedly with i millisecond each cycle
// stopCycleF(t): halt execute cycleF via the Timer return of cycleF
// 
// EX:
//   delayF(new Runnable()public void run() sig("Hi"); ,2000);
//   final Runnable rn=delayF(new Runnable()public void run() sig("Hi"); ,3000);
//     delayF(new Runnable()public void run() (new Handler()).post(rn);sig("Hello"); ,1000);
//   final Timer tm=cycleF(new Runnable() public void run() sig("Neverend"); , 1000);
//     delayF(new Runnable()public void run() stopCycleF(tm);sig("Ended"); ,7000);
//
public static Runnable delayF(final Runnable r, long delay) 
    final Handler h = new Handler();
    h.postDelayed(r, delay);
    return new Runnable()
        @Override
        public void run()h.removeCallbacks(r);
    ;

public static Timer cycleF(final Runnable r, long interval) 
    final Timer t=new Timer();
    final Handler h = new Handler();
    t.scheduleAtFixedRate(new TimerTask() 
            public void run() h.post(r);
        , interval, interval);
    return t;

public void stopCycleF(Timer t)t.cancel();t.purge();
public boolean serviceRunning(Class<?> serviceClass) 
    ActivityManager manager = (ActivityManager) getSystemService(Context.ACTIVITY_SERVICE);
    for (ActivityManager.RunningServiceInfo service : manager.getRunningServices(Integer.MAX_VALUE)) 
        if (serviceClass.getName().equals(service.service.getClassName())) 
            return true;
        
    
    return false;

//////////
///END//// RUNTIME //////////
//////////