SQL 按时间统计

Posted 2023-05-01

参考技术A 解决方法一:子查询
select
t1.part
,sum((select
t2.record
from
tablexxx
as t2
where
t2.part
=
t1.part
and t1.date
=
t2.date
and t2.date like
'%-4' ))
,sum((select
t2.record
from
tablexxx
as t2
where
t2.part
=
t1.part
and t1.date
=
t2.date
and t2.date like
'%-5' ))
--你需要统计几个日期就写几句子查询
from
tablexxx
as t1
解决方法二:decode
select
part
,sum(decode(date,'2010-4',record,''))
,sum(decode(date,'2010-5',record,''))
,sum(decode(date,'2010-6',record,''))
,sum(decode(date,'2010-7',record,''))
--同样根据需要写N条sum(decode(....))
from tablexxx group
by
part 参考技术B 如果你想要的输出是以date数据为列名，以part数据为行名，显示record的数据于表中，可用PIVOT做。下面例子是思路：
SELECT
[part],[d1],[d2],[d3],
...
FROM
(

SELECT
[date]
as
d,[part],[record]
FROM
[your_table]
)
AS
Dvtbl
PIVOT
(

MAX([record])

FOR
[d]
IN

(
[d1],
[d2],

[d3],

.... )
)
AS
Pvt

对“SELECT
[date]
as
d
”中的[date]进行处理（比如用相应的Date函数如datepart），就可以变幻出你所要设定的（按天，按月，按季度，按年）。d1,
d2,
d3,
....等等就是与[date]对应于的d的数据。
这只是个思路，具体写法根据你设定方案而有些不同。

sql 按月份统计数据的SQL语句

SELECT count(ht_id) as c,FROM_UNIXTIME(apply_time,'%Y%m') as monthly FROM t_hunt_talents group by FROM_UNIXTIME(apply_time,'%Y%m');