Little Boxes UVALive - 8209

Posted 2021-08-01 Jozky86

Little Boxes UVALive - 8209

题意：

给你四个数，输出四个数之和，四个数小于等于2⁶²之内

题解：

这。。。这。。水题
unsigned int 0～4294967295 (10位数，4e9)

int -2147483648～2147483647 (10位数，2e9 2^31 - 1)

long long： -9223372036854775808～9223372036854775807 (19位数， 9e18 ) 2^63 - 1

unsigned long long：0～18446744073709551615 (20位数，1e19) 2^64 - 1

代码：

#include <bits/stdc++.h>
using namespace std;
#define asd cout<<" SB "<<endl;
#define ll long long
#define INF 0x3f3f3f3f
int main(){
	int t;
	cin>>t;
	while(t--){
		ll a,b,c,d;
		cin>>a>>b>>c>>d;
		cout<<a+b+c+d<<endl;
	}
	
	return 0;
}

---

貌似是因为数据太水longlong才能过
大数操作用java

import java.math.BigInteger;
import java.util.Scanner;
 
public class Main {
    public static Scanner s = new Scanner(System.in);
 
    public static void main(String args[]) throws Exception {
	Scanner in = new Scanner(System.in);
        int t = in.nextInt();
        while(t-- != 0) {
            BigInteger a = in.nextBigInteger();
            BigInteger b = in.nextBigInteger();
            BigInteger c = in.nextBigInteger();
            BigInteger d = in.nextBigInteger();
            System.out.println(a.add(b.add(c.add(d))));
        }
 
    }
}

c++模拟也可以

#include<iostream>
 
using namespace std;
const int L=110;
string add(string a,string b){
	string ans;
	int na[L]={0},nb[L]={0};
	int la=a.size(),lb=b.size();
	for(int i=0;i<la;i++){
		na[la-1-i]=a[i]-'0';
	}
	for(int i=0;i<lb;i++){
		nb[lb-1-i]=b[i]-'0';
	}
	int lmax=la>lb?la:lb;
	for(int i=0;i<lmax;i++) na[i]+=nb[i],na[i+1]+=na[i]/10,na[i]%=10;
	if(na[lmax]) lmax++;
	for(int i=lmax-1;i>=0;i--) ans+=na[i]+'0';
	return ans;
}
string a,b,c,d;
int main(){
	ios::sync_with_stdio(0);
	cin.tie(0),cout.tie(0);
	int T;
	cin>>T;
	while(T--){
		cin>>a>>b>>c>>d;
		a=add(a,b);
		c=add(c,d);
		a=add(a,c);
		cout<<a<<endl;
	}
	return 0;
}