如何将interface 转成struct数组

Posted 2023-04-13

C#里面把struct转换成byte[]发送要你自己写函数把一个一个的成员binaryWriter发送， 接收的时候也是一个一个的binaryReader,再赋值给自己的结构成员。 C++比较好做一点，可以用指针直接把struct转换为byte[],不过要和C#通讯的话 参考技术A 可以考虑先初始化你的struct,然后在做Unmarshal。 package main import ( "fmt" "encoding/json" ) func main()

如何将字符串转换为hive中的struct数组并进行爆炸？

我在hive中有以下格式的数据。表test(seq string, result string);

|seq  | result                                                                                                                                                                                                                                                                                                                                                 |
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
|0001 | [{"offerId":"Default_XYZ","businessName":"Apple","businessGroup":"Default","businessIssue":"Default","interactionId":"-4930126168287369915","campaignID":"P-1","rank":"1"},{"offerId":"Default_NAV","businessName":"Orange","businessGroup":"Default","businessIssue":"Default","interactionId":"-7830126168223452134","campaignID":"P-1","rank":"2"}] |

输出应该是这样的

|seq  | offerId     | businessName   | businsesGroup| businessIssue | interactionId        | campaignId | rank |
----------------------------------------------------------------------------------------------------------------
|0001 | Default_XYZ | Apple          | Default      | Default       | -4930126168287369915 | P-1        | 1    |
|0001 | Default_NAV | Orange         | Default      | Default       | -7830126168223452134 | P-1        | 2    |

我试图将字符串转换为结构数组，但它不适用于直接CAST。

有什么帮助吗？

[编辑 - 尝试以下查询]

 select sequenceNumber, offerId, businessName, rank from (

 select sequenceNumber,
        collect_list(oid['offerId']) as offerid_list
       , collect_list(oid['businessName']) as businessName_list
        ,collect_list(oid['rank']) as rank_list
  from (
 select sequenceNumber,
        str_to_map(translate(offer_Id,'{}','')) as oid

        from test
        lateral view explode (split(translate(result, '[]"',''),"\},")) oid as offer_id
    ) x
    group by sequenceNumber

      ) y lateral view explode(offerid_list) olist as offerId
      lateral view explode(businessName_list) olist as businessName
      lateral view explode(rank_list) rlist as rank

答案

找到我的问题的一个解决方案：

select                                                   
seq, 
split(split(results,",")[0],':')[1] as offerId,
split(split(results,",")[1],':')[1] as businessName,
split(split(results,",")[2],':')[1] as businessGroup,
split(split(results,",")[3],':')[1] as businessIssue,
split(split(results,",")[4],':')[1] as interactionId,
split(split(results,",")[5],':')[1] as campignId
regexp_replace(split(split(results,",")[6],":")[1], "[\]|}]", "") as  rank

from
(
  select seq,
     split(translate(result), '"\[|]|""',''), "},") as r
      from test  
) t1
LATERAL VIEW explode(r) rr AS results

另一答案

你可以尝试get_json_object功能。

select seq, get_json_object(result,'$[0].offerId') as offerId,
            get_json_object(result,'$[0].businessName') as businessName,
            get_json_object(result,'$[0].businsesGroup') as businsesGroup,
            get_json_object(result,'$[0].businessIssue') as businessIssue,
            get_json_object(result,'$[0].interactionId') as interactionId,
            get_json_object(result,'$[0].campaignId') as campaignId,
            get_json_object(result,'$[0].rank') as rank
    from t
    UNION ALL
select seq, get_json_object(result,'$[1].offerId') as offerId,
            get_json_object(result,'$[1].businessName') as businessName,
            get_json_object(result,'$[1].businsesGroup') as businsesGroup,
            get_json_object(result,'$[1].businessIssue') as businessIssue,
            get_json_object(result,'$[1].interactionId') as interactionId,
            get_json_object(result,'$[1].campaignId') as campaignId,
            get_json_object(result,'$[1].rank') as rank
    from t