HQL作业

Posted 2021-07-23 安小猿

员工信息表emp：
字段：员工id,员工名字,工作岗位,部门经理,受雇日期,薪水,奖金,部门编号
英文名：EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,BONUS,DEPTNO

create table emp(
    EMPNO int
    ,ENAME string
    ,JOB string
    ,MGR int
    ,HIREDATE string
    ,SAL int
    ,BONUS int
    ,DEPTNO int
) 
row format delimited
fields terminated by ',';




7369,SMITH,CLERK,7902,1980-12-17,800,null,20
7499,ALLEN,SALESMAN,7698,1981-02-20,1600,300,30
7521,WARD,SALESMAN,7698,1981-02-22,1250,500,30
7566,JONES,MANAGER,7839,1981-04-02,2975,null,20,
7654,MARTIN,SALESMAN,7698,1981-09-28,1250,1400,30
7698,BLAKE,MANAGER,7839,1981-05-01,2850,null,30
7782,CLARK,MANAGER,7839,1981-06-09,2450,null,10
7788,SCOTT,ANALYST,7566,1987-04-19,3000,null,20
7839,KING,PRESIDENT,null,1981-11-17,5000,null,10
7844,TURNER,SALESMAN,7698,1981-09-08,1500,0,30
7876,ADAMS,CLERK,7788,1987-05-23,1100,null,20
7900,JAMES,CLERK,7698,1981-12-03,950,null,30
7902,FORD,ANALYST,7566,1981-12-03,3000,null,20
7934,MILLER,CLERK,7782,1982-01-23,1300,null,10


1600 1250 2850 1500 950
部门信息表dept：
字段：部门编号,部门名称,部门地点
英文名：DEPTNO,DEPTNAME,DEPTADDR

create table dept(
    DEPTNO int
    ,DEPTNAME string
    ,DEPTADDR string
) 
row format delimited
fields terminated by ',';


10,ACCOUNTING,NEW YORK
10,ACCOUNTING,shanghai
20,RESEARCH,DALLAS
30,SALES,CHICAGO
40,OPERATIONS,BOSTON

1． 列出至少有一个员工的所有部门。 
select deptno,count(*) sum from emp group by deptno having sum>1 ;


2． 列出薪金比“SMITH”多的所有员工。 
##在mysql中可以使用,在HIVE中不支持不等式子查询
##select * from emp where sal>(select sal from emp where ename='SMITH');

select * 
from (select 1 as tmp_id,empno,ename,sal from emp where ename!='SMITH') t1
left join (select 1 as tmp_id,sal from emp where ename='SMITH')  t2
on t1.emp_id = t2.emp_id 
where t1.sal > t2.sal;

3． 列出所有员工的姓名及其直接上级的姓名。 
select emp1.ename,emp2.ename from emp emp1 left join (select empno,ename from emp ) emp2 on emp1.mgr=emp2.empno;

4． 列出受雇日期早于其直接上级的所有员工。 
select emp1.* 
from emp emp1
left join emp emp2
on emp1.mgr=emp2.empno
where emp1.hiredate< emp2.hiredate;		


5． 列出部门名称和这些部门的员工信息，同时列出那些没有员工的部门。 
select dept.deptname,emp.* from dept left join emp on dept.deptno=emp.deptno;

6． 列出所有“CLERK”（办事员）的姓名及其部门名称。
select emp.ename,dept.deptname from emp left join dept on emp.deptno=dept.deptno  where emp.job='CLERK';

7． 列出最低薪金大于1500的各种工作。
select distinct job ,min(sal) min_sal from emp where min_sal>1500;

8． 列出在部门“SALES”（销售部）工作的员工的姓名，假定不知道销售部的部门编号
select  ename from emp emp1 left join dept on emp.deptno = dept.deptno where deptname='SALES';

9． 列出薪金高于公司平均薪金的所有员工。 
##select * from emp where sal>(select avg(sal) from emp);
##SQL中可用，HQL中不可用

select emp1.* 
from (select 1 as tmp_id,* from emp) emp1
left join (select 1 as tmp_id,avg(sal) avg_sal from emp ) emp2
on emp1.tmp_id = emp2.tmp_id
where emp1.sal>emp2.avg_sal;

10．列出与“SCOTT”从事相同工作的所有员工。
select * from emp emp1 where ename != 'SCOTT' and job in (select job from emp emp2 where ename='SCOTT');

11．列出薪金等于部门30中员工的薪金的所有员工的姓名和薪金。
select ename,sal from emp emp1 where sal in (select sal from emp emp2 where deptno=30);

12．列出薪金高于在部门30工作的所有员工的薪金的员工姓名和薪金。 
##select ename,sal from emp where sal >(select min(sal) from emp where deptno=30);
##SQL中可用，HQL中不可用

select emp1.ename,emp1.sal 
from (select 1  tmp_id , ename,sal from emp ) emp1
left join  (select 1 tmp_id,sal from emp where deptno=30) emp2 
on emp1.tmp_id=emp2.tmp_id
where emp1.sal >emp2.sal;

13．列出在每个部门工作的员工数量、平均工资和平均服务期限。
select count(*) sum,avg(sal+(case when bonus is null then 0 else bonus end)) avg_money,avg(datediff(current_date,hiredate)) avg_time from emp group by deptno;

14．列出所有员工的姓名、部门名称和工资。 
select ename,deptname,sal+(case when bonus is null then 0 else bonus end) from emp left join dept on emp.deptno=dept.deptno ;

15．列出所有部门的详细信息和部门人数。 
select dept.*,sum from dept left join (select deptno,count(*) sum from emp group by deptno) emp1 on dept.deptno=emp1.deptno; 

16．列出各种工作的最低工资。 
select min(sal+(case when bonus is null then 0 else bonus end)) from emp group by job;

17．列出各个部门的MANAGER（经理）的最低薪金。
select sal from emp emp1 where sal=(select min(sal)  from emp emp2 where emp1.deptno=emp2.deptno);

18．列出所有员工的年工资,按年薪从低到高排序。
select 12*(sal+(case when bonus is null then 0 else bonus end)) sum_sal from emp order by sum_sal;

19. 列出每个部门薪水前两名最高的人员名称以及薪水。
select ename,sal from emp emp1 where 2>(select count(*) from emp emp2 where emp1.deptno=emp2.deptno and emp1.sal<emp2.sal);


select emp1.ename,emp1.sal from (select ename,sal,row_number() over (partition by deptno order by sal desc ) as rn from emp ) emp1 where rn<=2;

20. 列出每个员工从受雇开始到2018-12-12 为止共受雇了多少天。
select *,datediff('2018-12-12',hiredate) from emp;