C语言实现简易日历(附源码)

Posted 2021-07-19 不倒翁*

C语言实现简易日历
首先来看程序运行的结果,首先会提示用户输入年份和月份,就会以日历的形式打印出这个月的信息.

下面来看看程序设计源码:

#define _CRT_SECURE_NO_WARNINGS 1 //避免vs中scanf报错
#include <stdio.h>
int main()
{
	int year = 0;
	int month = 0;
	printf("请输入年份:");
	scanf("%d", &year);
	printf("请输入月份:");
	scanf("%d", &month);
	printf("一\\t二\\t三\\t四\\t五\\t六\\t日\\n");
	int day = 0;
	for (int i = 1900; i < year; i++)//将输入年之前的年份天数求和
	{
		//判断是否为闰年
		if ((i % 4 == 0 && i % 100 == 0) || (i % 400 == 0))
		{
			day += 366;
		}
		else
		{
			day += 365;
		}
	}

	int day1 = 0;
	//判断月数
	for (int m = 1; m <= month; m++)
	{
		switch (m)
		{
		case 4:
		case 6:
		case 9:
		case 11:
			day1 = 30;
			break;
		case 2:
			if ((year % 4 == 0 && year % 100 == 0) || (year % 400 == 0))
			{
				day1 =29;
			}
			else
			{
				day1 = 28;
			}
			break;
		default:
			day1 = 31;
			break;
		}
		if (m < month)
		{
			day += day1; //将输入年中的每月统计到总天数中
		}
	}
	int t = day % 7;
	for (int i = 0; i < t; i++)
	{
		printf("\\t");
	}

	for (int i = 1; i <=day1; i++)
	{
		printf("%d\\t", i );
		if ((i + day) % 7 == 0)
		{
			printf("\\n");
		}

	}
	printf("\\n");
	return 0;
}