LeetCode:Database 71.报告系统状态的连续日期
Posted Xiao Miao
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了LeetCode:Database 71.报告系统状态的连续日期相关的知识,希望对你有一定的参考价值。
要求:编写一个 SQL 查询 2019-01-01 到 2019-12-31 期间任务连续同状态 period_state 的起止日期(start_date 和 end_date)。
系统 每天 运行一个任务。每个任务都独立于先前的任务。任务的状态可以是失败或是成功,如果任务失败了,就是失败状态的起止日期,如果任务成功了,就是成功状态的起止日期,最后结果按照起始日期 start_date 排序。
Table: Failed的结构
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| fail_date | date |
+--------------+---------+
该表主键为 fail_date。
该表包含失败任务的天数.
Table: Succeeded的结构
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| success_date | date |
+--------------+---------+
该表主键为 success_date。
该表包含成功任务的天数.
Failed 表:
+-------------------+
| fail_date |
+-------------------+
| 2018-12-28 |
| 2018-12-29 |
| 2019-01-04 |
| 2019-01-05 |
+-------------------+
Succeeded 表:
+-------------------+
| success_date |
+-------------------+
| 2018-12-30 |
| 2018-12-31 |
| 2019-01-01 |
| 2019-01-02 |
| 2019-01-03 |
| 2019-01-06 |
+-------------------+
Result Table:
+--------------+--------------+--------------+
| period_state | start_date | end_date |
+--------------+--------------+--------------+
| succeeded | 2019-01-01 | 2019-01-03 |
| failed | 2019-01-04 | 2019-01-05 |
| succeeded | 2019-01-06 | 2019-01-06 |
+--------------+--------------+--------------+
结果忽略了 2018 年的记录,因为我们只关心从 2019-01-01 到 2019-12-31 的记录
从 2019-01-01 到 2019-01-03 所有任务成功,系统状态为 "succeeded"。
从 2019-01-04 到 2019-01-05 所有任务失败,系统状态为 "failed"。
从 2019-01-06 到 2019-01-06 所有任务成功,系统状态为 "succeeded"。
SQL语句:
#1.方法1
SELECT * FROM(
SELECT 'failed' AS period_state,MIN(fail_date) AS start_date ,MAX(fail_date) AS end_date
FROM(
SELECT fail_date,ADDDATE(fail_date,-row_number() over(ORDER BY fail_date ASC)) AS r
FROM failed
WHERE fail_date BETWEEN '2019-01-01' AND '2019-12-31'
)a
GROUP BY r
UNION ALL
SELECT 'succeeded' AS period_state,MIN(success_date)AS start_date,MAX(success_date)AS end_date
FROM(
SELECT success_date,ADDDATE(success_date,-row_number() over(ORDER BY success_date ASC)) AS r
FROM succeeded
WHERE success_date BETWEEN '2019-01-01' AND '2019-12-31'
)a
GROUP BY r)b
ORDER BY start_date ASC;
#2.方法2
select period_state,min(d) as start_date,max(d) as end_date
from(
select 'failed' AS period_state,fail_date as d,adddate(fail_date,-row_number() over(order by fail_date asc)) as r
from failed
union all
SELECT 'succeeded' AS period_state,success_date AS d,ADDDATE(success_date,-row_number() over(ORDER BY success_date ASC)) AS r
FROM succeeded
)a
where d between '2019-01-01' and '2019-12-31'
GROUP BY r,period_state
order by start_date asc;
以上是关于LeetCode:Database 71.报告系统状态的连续日期的主要内容,如果未能解决你的问题,请参考以下文章
LeetCode:Database 103.周内每天的销售情况