Hive full join 对数 排查异常数据
Posted 二十六画生的博客
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select
t1.*,
t2.*
from (
select 1 as c1 , 'a' as c2
union all
select 2 as c1 , 'b' as c2
union all
select 3 as c1 , null as c2
union all
select 4 as c1 , 'd' as c2
)t1
full join
(
select 2 as c1 , 'b' as c2
union all
select 3 as c1 , null as c2
union all
select 4 as c1 , 'd4' as c2
union all
select 5 as c1 , 'e' as c2
)t2
on t1.c1 = t2.c1
order by coalesce(t1.c1 , t2.c1 ) ; -- 5条记录
select
t1.*,
t2.*
from (
select 1 as c1 , 'a' as c2
union all
select 2 as c1 , 'b' as c2
union all
select 3 as c1 , null as c2
union all
select 4 as c1 , 'd' as c2
)t1
full join
(
select 2 as c1 , 'b' as c2
union all
select 3 as c1 , null as c2
union all
select 4 as c1 , 'd4' as c2
union all
select 5 as c1 , 'e' as c2
)t2
on t1.c1 = t2.c1
where t1.c1 is null or t2.c1 is null or (coalesce(t1.c2,'') <> coalesce(t2.c2,''))
order by coalesce(t1.c1 , t2.c1 ) ; -- 3条记录
select
t1.*,
t2.*
from (
select 1 as c1 , 'a' as c2
union all
select 2 as c1 , 'b' as c2
union all
select 3 as c1 , null as c2
union all
select 4 as c1 , 'd' as c2
)t1
full join
(
select 2 as c1 , 'b' as c2
union all
select 3 as c1 , null as c2
union all
select 4 as c1 , 'd4' as c2
union all
select 5 as c1 , 'e' as c2
)t2
on t1.c1 = t2.c1
where (coalesce(t1.c2,'') <> coalesce(t2.c2,''))
order by coalesce(t1.c1 , t2.c1 ) ; -- 3条记录 ,是包含第二种条件的结果的，
-- 所以【t1.c1 is null or t2.c1 is null】这个条件就不用写了！一的结果：
二 三的结果：
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