mysql语法错误:Every derived table must have its own alias
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mysql查询报错如图
报错原因
every derived table must have it own
alias 翻译过来就是:每一个派生出来的表都必须有一个自己的别名。
就是说子查询没有别名
解决方案
给子查询起个别名,可以写成这种形式
select count(*) from (select * from ……) as total;
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mysql union出错: "Every derived table must have its own alias"
ERROR 1248 (42000): Every derived table must have its own alias