c语言扫雷小游戏

Posted 2021-06-14 ~千里之行，始于足下~

用c语言实现扫雷小游戏

game.h

#pragma once
#include<stdio.h>
#include<string.h>
#include<time.h>
#include<stdlib.h>
#include<windows.h>
#pragma warning(disable:4996)
#define ROW 12
#define COL 12
#define STYLE '*'     //棋盘风格
#define MINE_COUNT 20 //棋盘的风格

extern void game();

game.c

#include"game.h"
//埋雷
static void setMines(char board[][COL], int row, int col)
{
	int count = MINE_COUNT;
	while (count)
	{
		int x = rand() % (ROW - 2) + 1;
		int y = rand() % (COL - 2) + 1;
		if (board[x][y] == '0')//1是雷，0不是雷
		{
			board[x][y] = '1';
			count--;
		}
	}
}

static void ShowLine(int col)
{
	for (int i = 0; i <= (col - 2); i++){
		printf("----");
	}
	printf("\\n");
}

static void showMyBoard(char board[][COL], int row, int col)
{
	printf("     ");
	for (int i = 1; i <= (col - 2); i++){
		printf("%d   ", i);
	}
	printf("\\n");
	ShowLine(col);
	for (int i = 1; i <= (row - 2); i++){
		printf("%-3d|", i);
		for (int j = 1; j <= (col - 2); j++){
			printf(" %c |", board[i][j]);
		}
		printf("\\n");
		ShowLine(col);
	}
}

//返回该位置周围雷的数量
static int countMines(char board[][COL], int x, int y)
{
	return board[x - 1][y - 1] + board[x - 1][y] + board[x - 1][y + 1] + \\
		board[x][y + 1] + board[x + 1][y + 1] + board[x + 1][y] + \\
		board[x + 1][y - 1] + board[x][y - 1] - 7 * '0';
}

void game()
{
	srand((unsigned long)time(NULL));
	char showBoard[ROW][COL];  //已排雷的位置为雷的数量
	char mineBoard[ROW][COL];  //雷盘，都是0或1字符
	memset(showBoard, STYLE, sizeof(showBoard));
	memset(mineBoard, '0', sizeof(mineBoard));
	setMines(mineBoard, ROW, COL);
	int x = 0;
	int y = 0;
	int row = ROW;
	int col = COL;
	int mineCount = MINE_COUNT;
	int cnt = (row - 2) * (COL - 2) - mineCount;//排雷的次数
		while (cnt)
		{
			system("cls");
			showMyBoard(showBoard, ROW, COL);
			printf("please the position: \\n");
			scanf("%d %d", &x, &y);
			if (x < 1 || x > 10 || y < 1 || y > 10)
			{
				printf("Position error!\\n");
				continue;
			}
			if (showBoard[x][y] != STYLE)
			{
				printf("position is not *\\n");
				continue;
			}
			if (mineBoard[x][y] == '1')
			{
				printf("game over!\\n");
				showMyBoard(mineBoard, ROW, COL);
				system("pause");
				system("cls");
				break;
			}
			showBoard[x][y] = countMines(mineBoard, x, y);
			cnt--;
		}
}

main.c

#include"game.h"

void menu()
{
	printf("|+++++++++++++++++++++++++++++++++++|\\n");
	printf("|+++1. play               0. exit+++|\\n");
	printf("|+++++++++++++++++++++++++++++++++++|\\n");
}
int main()
{
	int quit = 0;
	while (!quit)
	{
		menu();
		int select = 0;
		printf("请输入您的选择： \\n");
		scanf("%d", &select);
		switch (select)
		{
		case 1: //printf("开始游戏\\n");
			game();
			break;
		case 0:
			quit = 1;
			printf("欢迎使用！\\n");
			break;
		default:
			printf("输入错误!\\n");
		}
	}
	system("pause");
	return 0;
}

这个扫雷游戏设计最妙之处就是12 * 12的棋盘，实际使用了10 * 10，原因是为了方便计算排完雷位置周围雷的数量。