简单实现你想数字电脑猜的小游戏

Posted 2021-06-11 两片空白

一实现功能

你心中想一个数字，电脑来猜，通过你输入该数大了还是小了，来重新确定范围，直到电脑猜对。

二.代码

#include<stdio.h>
#include<windows.h>
#include<time.h>
void Menu(){
	printf("+---------------+\\n");
	printf("+-1.Play 2.Exit-+\\n");
	printf("+---------------+\\n");
	printf("Please Enter You Select\\n");
}
int Computer_guess(int max, int min){
	while (1){
		int x = rand() % 100 + 1;
		if (x >= min&&x <= max){
			return x;
			break;
		}
	}
}

void Game(){
	char ans[10];
	int min = 0;
	int max = 100;
	int x = rand() % 100 + 1;
	printf("Please think of a number <1-100>\\n");
	Sleep(3000);
	while (1){

		printf("Is it %d\\n", x);
		scanf("%s", ans);
		if (strcmp(ans, "big") == 0){
			max = x - 1;
		}
		else if (strcmp(ans, "small") == 0){
			min = x + 1;
		}
		else if (strcmp(ans, "right") == 0){
			break;
		}
		else{
		}
		x = Computer_guess(max,min);
	}
	printf("you lose!\\n");

}
int main()
{
	srand((unsigned long)time(NULL));
	int quit = 0;
	while (!quit){
		system("cls");
		Menu();
		int select = 0;
		scanf("%d", &select);
		switch (select){
		case 1:
			Game();
			break;
		case 2:
			quit = 1;
			break;
		default:
			printf("Enter error,Try again\\n");
			break;
		}

	}
	return 0;
}

假如我们想的结果是50