无重复字符的最长子串（并输出相应的最长子串）

Posted 2021-05-29 zhou753099943

/*
 * 给定一个字符串，请你找出其中不含有重复字符串的最长子串的长度，
 * 新增一个附加条件：并输出相应的最长子串字符
*/
#include <unordered_set>
void testMaxChar()
{
    //"abcabcbb"
    //char *src="abcabcbb";
    char *src="abcabcbbxyzwertoziabdcw";

    // 官方答案
    {
        std::string s="abcabcbbxyzwertoziabdcw";
        std::unordered_set<char> ooc;
        int n = s.size();
        int rk = -1;
        int ans = 0;
        for(int i = 0; i < n; ++i)
        {
            if (i != 0)
                ooc.erase(s[i - 1]);

            while (rk + 1 < n && !ooc.count(s[rk + 1])) {
               ooc.insert(s[rk + 1]);
               ++rk;
            }
            ans = std::max(ans, rk -i + 1);
        }
        for(auto it : ooc)
            std::cout<<it<<",";
         std::cout<<"  ans:"<<ans<<std::endl;
    }
    std::vector<char> vector;
    std::vector<char> vector2;
    while (*src != '\\0')
    {
        size_t i= 0;
        bool find = false;
        while(i < vector.size())
        {
            if (*src == vector[i])
            {
                find = true;
                if (vector.size() > vector2.size())
                {
                    vector2.clear();
                    vector2 = vector;
                }
                ++i;
                break;
            }
            ++i;
        }
        if (i < vector.size())
        {
            std::vector<char> vector4;
            for(;i < vector.size(); ++i)
                vector4.push_back(vector[i]);
            vector.clear();
            vector = vector4;
        }
        else if (find && i >= vector.size())
            vector.clear();
        vector.push_back(*src);
        src++;
    }

    std::vector<char> vector_result;
    if (vector2.size() > vector.size())
        vector_result = vector2;
    else
        vector_result = vector;

    for(size_t i =0; i < vector_result.size(); ++i)
    {
        std::cout<<vector_result[i]<<",";
    }
    std::cout<<"  size:"<<vector_result.size()<<std::endl;
}