[PTA]实验8-1-2 计算两数的和与差

Posted 2021-05-26 Spring-_-Bear

本题要求实现一个计算输入的两数的和与差的简单函数。

函数接口定义：

void sum_diff( float op1, float op2, float *psum, float *pdiff );

其中op1和op2是输入的两个实数，psum和pdiff是计算得出的和与差。

裁判测试程序样例：

#include <stdio.h>

void sum_diff( float op1, float op2, float *psum, float *pdiff );

int main()
{
    float a, b, sum, diff;

    scanf("%f %f", &a, &b);
    sum_diff(a, b, &sum, &diff);
    printf("The sum is %.2f\\nThe diff is %.2f\\n", sum, diff);

    return 0; 
}

/* 你的代码将被嵌在这里 */

输入样例：

4 6

输出样例：

The sum is 10.00
The diff is -2.00

• 提交结果：

• 源码：

#include <stdio.h>

void sum_diff(float op1, float op2, float* psum, float* pdiff);

int main()
{
    float a, b, sum, diff;

    scanf("%f %f", &a, &b);
    sum_diff(a, b, &sum, &diff);
    printf("The sum is %.2f\\nThe diff is %.2f\\n", sum, diff);

    return 0;
}

/* 你的代码将被嵌在这里 */
void sum_diff(float op1, float op2, float* psum, float* pdiff)
{
    *psum = op1 + op2;
    *pdiff = op1 - op2;
}