LeetCode（数据库）- 重新格式化部门表

Posted 2021-05-24 Lux_Sun

题目链接：点击打开链接

 

题目大意：略。

 

解题思路：

第一步 列拆成行

首先，根据题意，需要将revenue列根据month拆成行，结果如下表，有两种方式，CASE WHEN或者IF语句。

SELECT id,
CASE `month` WHEN 'Jan' THEN revenue END Jan_Revenue,
CASE `month` WHEN 'Feb' THEN revenue END Feb_Revenue,
CASE `month` WHEN 'Mar' THEN revenue END Mar_Revenue,
CASE `month` WHEN 'Apr' THEN revenue END Apr_Revenue,
CASE `month` WHEN 'May' THEN revenue END May_Revenue,
CASE `month` WHEN 'Jun' THEN revenue END Jun_Revenue,
CASE `month` WHEN 'Jul' THEN revenue END Jul_Revenue,
CASE `month` WHEN 'Aug' THEN revenue END Aug_Revenue,
CASE `month` WHEN 'Sep' THEN revenue END Sep_Revenue,
CASE `month` WHEN 'Oct' THEN revenue END Oct_Revenue,
CASE `month` WHEN 'Nov' THEN revenue END Nov_Revenue,
CASE `month` WHEN 'Dec' THEN revenue END Dec_Revenue
FROM Department;

或

SELECT id,
IF(`month`='Jan',revenue,NULL) Jan_Revenue,
IF(`month`='Feb',revenue,NULL) Feb_Revenue,
IF(`month`='Mar',revenue,NULL) Mar_Revenue,
IF(`month`='Apr',revenue,NULL) Apr_Revenue,
IF(`month`='May',revenue,NULL) May_Revenue,
IF(`month`='Jun',revenue,NULL) Jun_Revenue,
IF(`month`='Jul',revenue,NULL) Jul_Revenue,
IF(`month`='Aug',revenue,NULL) Aug_Revenue,
IF(`month`='Sep',revenue,NULL) Sep_Revenue,
IF(`month`='Oct',revenue,NULL) Oct_Revenue,
IF(`month`='Nov',revenue,NULL) Nov_Revenue,
IF(`month`='Dec',revenue,NULL) Dec_Revenue
FROM Department;

+------+-------------+-------------+-------------+-----+-------------+
| id   | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
+------+-------------+-------------+-------------+-----+-------------+
| 1    | null        | 7000        | null        | ... | null        |
| 3    | null        | 10000       | null        | ... | null        |
| 1    | 8000        | null        | null        | ... | null        |
| 2    | 9000        | null        | null        | ... | null        |
| 1    | null        | null        | 6000        | ... | null        |
+------+-------------+-------------+-------------+-----+-------------+

第二步 行合并

其次，根据题意，需要根据id，将相同id的行进行合并，结果如下表，采用分组的方式，可以对各月收入列求和（SUM）也可以求最大值(MAX)。

SELECT id,
SUM(CASE `month` WHEN 'Jan' THEN revenue END) Jan_Revenue,
SUM(CASE `month` WHEN 'Feb' THEN revenue END) Feb_Revenue,
SUM(CASE `month` WHEN 'Mar' THEN revenue END) Mar_Revenue,
SUM(CASE `month` WHEN 'Apr' THEN revenue END) Apr_Revenue,
SUM(CASE `month` WHEN 'May' THEN revenue END) May_Revenue,
SUM(CASE `month` WHEN 'Jun' THEN revenue END) Jun_Revenue,
SUM(CASE `month` WHEN 'Jul' THEN revenue END) Jul_Revenue,
SUM(CASE `month` WHEN 'Aug' THEN revenue END) Aug_Revenue,
SUM(CASE `month` WHEN 'Sep' THEN revenue END) Sep_Revenue,
SUM(CASE `month` WHEN 'Oct' THEN revenue END) Oct_Revenue,
SUM(CASE `month` WHEN 'Nov' THEN revenue END) Nov_Revenue,
SUM(CASE `month` WHEN 'Dec' THEN revenue END) Dec_Revenue
FROM Department
GROUP BY id;

+------+-------------+-------------+-------------+-----+-------------+
| id   | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
+------+-------------+-------------+-------------+-----+-------------+
| 1    | 8000        | 7000        | 6000        | ... | null        |
| 2    | 9000        | null        | null        | ... | null        |
| 3    | null        | 10000       | null        | ... | null        |
+------+-------------+-------------+-------------+-----+-------------+