C语言 计算1+3+5+7+9+…+2*n-1的值

Posted 2021-05-20 Aiden (winner)

#include <stdio.h>
void main(){
    int i,n,sum1=0,sum2=0;
    printf("请输入项数：");
    scanf("%d",&n);
    for (i=1;i<n+1;i++){
        sum1=2*i-1;
        sum2+=sum1;
    }
    printf("sum = %d",sum2);
}