P5730 深基5.例10显示屏

Posted 2021-05-18 Kunkun只喝怡宝

题目描述

液晶屏上，每个阿拉伯数字都是可以显示成 3×5 的点阵的（其中 X 表示亮点，. 表示暗点）。现在给出数字位数（不超过 100）和一串数字，要求输出这些数字在显示屏上的效果。数字的显示方式如同样例输出，注意每个数字之间都有一列间隔。

代码

用五个二维数组分别存储每个数字每一行的三个字母，最后一行一行的输出就好了。

#include<bits/stdc++.h>

using namespace std;

int main(){
	int n,i;
	char a[100],
	b1[10][4]={"XXX","..X","XXX","XXX","X.X","XXX","XXX","XXX","XXX","XXX"},
	b2[10][4]={"X.X","..X","..X","..X","X.X","X..","X..","..X","X.X","X.X"},
	b3[10][4]={"X.X","..X","XXX","XXX","XXX","XXX","XXX","..X","XXX","XXX"},
	b4[10][4]={"X.X","..X","X..","..X","..X","..X","X.X","..X","X.X","..X"},
	b5[10][4]={"XXX","..X","XXX","XXX","..X","XXX","XXX","..X","XXX","XXX"};
	cin>>n>>a;
	for(i=0;i<n;i++){
		cout<<b1[a[i]-'0'];
		if(i<n-1) cout<<'.';
		else cout<<endl;
	}
	for(i=0;i<n;i++){
		cout<<b2[a[i]-'0'];
		if(i<n-1) cout<<'.';
		else cout<<endl;
	}for(i=0;i<n;i++){
		cout<<b3[a[i]-'0'];
		if(i<n-1) cout<<'.';
		else cout<<endl;
	}for(i=0;i<n;i++){
		cout<<b4[a[i]-'0'];
		if(i<n-1) cout<<'.';
		else cout<<endl;
	}for(i=0;i<n;i++){
		cout<<b5[a[i]-'0'];
		if(i<n-1) cout<<'.';
		else cout<<endl;
	}
	return 0;
}