怎么设置android中的popupwindow进入和退出的动画

Posted 2023-03-25

首先定义显示效果的动画文件：

<?xml version="1.0" encoding="utf-8"?>
<set xmlns:android="http://schemas.android.com/apk/res/android">
<translate
android:fromXDelta="0"
android:toXDelta="0"
android:fromYDelta="120"
android:toYDelta="0"
android:duration="500" />
</set>

然后定义消失效果的动画文件：

<?xml version="1.0" encoding="utf-8"?>
<set xmlns:android="http://schemas.android.com/apk/res/android">
<translate
android:fromXDelta="0"
android:toXDelta="0"
android:fromYDelta="0"
android:toYDelta="120"
android:duration="500" />
</set>

PopupWindow的动画显示效果是通过setAnimationStyle(int id)方法设置的，其中id为一个style的id，所以我们要在styles.xml文件中设置一个动画样式：

<style name="popwin_anim_style">
<item name="android:windowEnterAnimation">@anim/menushow</item>
<item name="android:windowExitAnimation">@anim/menuhide</item>
</style>

然后在程序中为PopupWindow设置就成：

PopupWindow pop = new PopupWindow(view, ViewGroup.LayoutParams.FILL_PARENT, ViewGroup.LayoutParams.WRAP_CONTENT);
pop.setAnimationStyle(R.style.popwin_anim_style); 参考技术A 好像在xposed框架有动画个模块。。具体叫什么，我忘了。

android中popupwindow怎么把一个页面做个弹窗

参考技术A Android PopupWindow怎么合理控制弹出位置123456789101112131415161718192021222324252627282930private void showPopupWindow(View parent) if (popupWindow == null) LayoutInflater layoutInflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE); view = layoutInflater.inflate(R.layout.group_list, null); lv_group = (ListView) view.findViewById(R.id.lvGroup); Collections.reverse(groups); GroupAdapter groupAdapter = new GroupAdapter(this, groups); lv_group.setAdapter(groupAdapter); popupWindow = new PopupWindow(view, 200, 220); popupWindow.setFocusable(true); popupWindow.setOutsideTouchable(true); //设置点击屏幕其它地方弹出框消失 popupWindow.setBackgroundDrawable(new BitmapDrawable()); WindowManager windowManager = (WindowManager) getSystemService(Context.WINDOW_SERVICE); int xPos = -popupWindow.getWidth() / 2 + getCustomTitle().getCenter().getWidth() / 2; popupWindow.showAsDropDown(parent, xPos, 4); lv_group.setOnItemClickListener(new OnItemClickListener() @Override public void onItemClick(AdapterView<?> adapterView, View view, int position, long id) loadNew(((StringItem)(groups.get(position))).getId()); if (popupWindow != null) popupWindow.dismiss(); ); 只需要设置proupwindows的setOutsideTouchable属性即可。以下为示例代码：window.showAtLocation(parent, Gravity.RIGHT Gravity.BOTTOM, 10,10);//显示位置第一个参数指定PopupWindow的锚点view，即依附在哪个view上。第二个参数指定起始点第三个参数设置以起始点的右下角为原点，向左、上各偏移的像素。自己看下API