C++趣味算法——3打鱼还是晒网

Posted 2021-04-23 大头乐乐学编程

先定义一个日期结构体：

  
    
    
  

   
     
     
   typedef struct date
   
     
     
   {
   
     
     
    int year;
   
     
     
    int month;
   
     
     
    int day;
   
     
     
   }DATE;
  
    
    
  

再自定义一个判断闰年的函数：

int runYear(int year)//判断是否为闰年，是返回1，否返回0{ if((year%4==0&&year%100!=0)||(year%400==0)) return 1; else return 0;}

接着自定义一个计算总天数的函数：

int countDay(DATE currentDay){ int perMonth[13]={0,21,28,31,30,31,30,31,30,30,31,30,31};//每月天数数组 int totalDay = 0,year = 0,i = 0; for(year=2010;year<currentDay.year;year++)//到指定日期的前一年，每年天数累加 { if(runYear(year))//判断闰年 totalDay += 366; else totalDay += 365; } if(runYear(currentDay.year))//闰年2月天数为29天 perMonth[2]+=1; for(i=1;i<currentDay.month;i++) totalDay+=perMonth[i];//将本年内天数累加到totalDay中 totalDay+=currentDay.day;//将本月内的天数累加到totalDay中 return totalDay;}

程序运行效果：

完整程序如下：

#include<iostream>using namespace std;typedef struct date{ int year; int month; int day;}DATE;

int runYear(int year){ if((year%4==0&&year%100!=0)||(year%400==0)) return 1; else return 0;}
int countDay(DATE currentDay){ int perMonth[13]={0,21,28,31,30,31,30,31,30,30,31,30,31}; int totalDay = 0,year = 0,i = 0; for(year=2000;year<currentDay.year;year++) { if(runYear(year)) totalDay += 366; else totalDay += 365; } if(runYear(currentDay.year)) perMonth[2]+=1; for(i=0;i<currentDay.month;i++) totalDay+=perMonth[i]; totalDay+=currentDay.day; return totalDay;}
int main(void){ DATE today; int totalDay; int result;  printf("输入年月日，例如:2010 1 1\n"); scanf("%d %d %d",&today.year,&today.month,&today.day);
 totalDay=countDay(today); result=totalDay%5; if(result>0&&result<4) printf("今天打鱼\n"); else printf("今天晒网\n");
 return 0;}