写了一个linux的计时脚本，能够输出时分秒

Posted 2023-02-23 CSU迦叶

#!/bin/bash

start=$(date +%s)

# 用需要计时的程序将下面这句替换掉
sleep 100;

end=$(date +%s)
take=$(( end - start ))
echo Time taken to execute commands is $take seconds.

let min=$take/60
let left1=$take-$(( $min * 60 ))

echo That is $min minutes and $left1 seconds.

let h=$take/3600
let left2=$min-$(( $h * 60 ))

echo That is $h hours and $left2 minutes.

输出

 里面用到了两种linux下的四则运算 let 以及 $ 

参考blog shell（7）：四则运算