Search in Rotated Sorted Array

Posted 2022-12-08 大数据最好

问题描述：

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

You are given a target value to search. If found in the array return its index, otherwise return -1.

You may assume no duplicate exists in the array.

实现代码：

public class Solution 
   public static int search(int[] nums, int target) 
		int index=0;
	    for(int i=0;i<nums.length-1;i++)
	    	if(nums[i] > nums[i+1])
	    		index = i+1;
	    		break;
	    	
	    
	    int left=0,right=nums.length-1;
	    if(target > nums[right])
	    	right=index-1;
	    else if(target < nums[right])
	    	left=index;
	    else if(index!=0 && target==nums[right])
	    	return right;
	    
	    index=(left+right)/2;
	    while(left <= right)
	    	System.out.println("000000");
	    	if(target < nums[index])
	    		right=index-1;
	    	else if(target > nums[index])
	    		left=index+1;
	    	else
	    		return index;
	    	
	    	index=(left+right)/2;
	    	
	    
		return -1;