Linux脚本练习之script083-nginx日志分析之查询某个IP的详细访问情况

Posted 2022-12-01 二木成林

script083

题目

注：题目来源于 SHELL26 nginx日志分析4-查询某个IP的详细访问情况 。

假设 nginx 的日志我们存储在 nowcoder.txt 里，格式如下：

192.168.1.20 - - [21/Apr/2020:14:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [21/Apr/2020:15:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [21/Apr/2020:21:27:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.23 - - [21/Apr/2020:22:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.24 - - [22/Apr/2020:15:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.25 - - [22/Apr/2020:15:26:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.20 - - [23/Apr/2020:08:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:09:20:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:10:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:10:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.20 - - [23/Apr/2020:14:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:15:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:15:27:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.25 - - [23/Apr/2020:16:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.24 - - [23/Apr/2020:20:27:49 +0800] "GET /2/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.25 - - [23/Apr/2020:20:27:49 +0800] "GET /3/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.20 - - [23/Apr/2020:20:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:20:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:20:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.22 - - [23/Apr/2020:22:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"
192.168.1.21 - - [23/Apr/2020:23:27:49 +0800] "GET /1/index.php HTTP/1.1" 404 490 "-" "Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:45.0) Gecko/20100101 Firefox/45.0"

现在需要你查询 192.168.1.22 的详细访问情况，按访问频率降序排序。你的脚本应该输出：

4 /1/index.php
2 /3/index.php

脚本一

首先通过 grep 命令查找到 IP 地址是 192.168.1.22 的记录行；然后通过 awk 命令提取第七列，即访问路径；然后通过 sort 命令对其进行排序；排序后重复路径相邻，所以可以通过 uniq -c 命令统计去重后的每条路径的出现次数；再通过 sort 命令按照访问频率降序排列；最后通过 awk 命令调整第一列和第二列的出现顺序，让出现次数在第一列，路径在第二列。

grep "192.168.1.22" nowcoder.txt  | awk 'print $7' | sort | uniq -c | sort -nr | awk 'print $1,$2'

脚本二

直接通过 awk 命令来进行正则表达式匹配，查找第七列路径列。

awk '/192.168.1.22/print $7' nowcoder.txt | sort | uniq -c | sort -nr | awk 'print $1,$2'

脚本三

利用了关联数组，将查找到的路径放进关联数组中，并统计其出现次数；再在 END 中打印关联数组中的路径和出现次数；最后使用 sort 命令降序排列。

awk '/192.168.1.22/map[$7]++ ENDfor(k in map) print map[k],k' nowcoder.txt | sort -nr