C语言 找数码是否存在

Posted 2022-11-29 ʚVVcatɞ

题目描述

定义一个函数check(n,d)，它送回一个结果。如果数字d在整数n的某位中出现，则送回“1”，否则送回“0”。例如check(3256,2)的返回值=1，check(1725,3)的返回值=0。编写完整程序效果如下

输入

41632,6

输出

The digit 6 is in data 41632

样例输入

25348,7

样例输出

The digit 7 is not in data 25348

#include "stdio.h"
int check(int n,int d);

int main()

	int num1,num2;
	printf("Enter n,d:");
	scanf("%d,%d",&num1,&num2);
	if(check(num1,num2)==1)
		printf("The digit %d is in data %d\\n",num2, num1);
	else 
		printf("The digit %d is not in data %d\\n",num2,num1);


int check(int n,int d)
	int result = 0; 
	if(n == 0)
		result++;
	
	while(n != 0)
		if(n % 10 == d)
			result++;
		
		n = n / 10;
	
	return result;