LeetCode 561 Array Partition I（数组划分）

Posted 2022-11-27 nomasp

翻译

原文

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), …, (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:
Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4.
Note:
n is a positive integer, which is in the range of [1, 10000].
All the integers in the array will be in the range of [-10000, 10000].

代码

 public int arrayPairSum(int[] nums) 
        Arrays.sort(nums);
        int sum = 0;
        for (int i = 0; i < nums.length; i+=2) 
            sum += nums[i];
        
        return sum;