CodeForces 670A Holidays

Posted 2023-02-21 Calm微笑

K - Holidays Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit  Status

Description

On the planet Mars a year lasts exactly n days (there are no leap years on Mars). But Martians have the same weeks as earthlings — 5 work days and then 2 days off. Your task is to determine the minimum possible and the maximum possible number of days off per year on Mars.

Input

The first line of the input contains a positive integer n (1 ≤ n ≤ 1 000 000) — the number of days in a year on Mars.

Output

Print two integers — the minimum possible and the maximum possible number of days off per year on Mars.

Sample Input

Input

14

Output

4 4

Input

2

Output

0 2

题意;给你n天，5天为工作日，2天为休息日，问最多可以休息几天，最少可以休息几天

#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int main()

	int n,min,max;
	while(scanf("%d",&n)!=EOF)
	
		min=0;
		max=0;
		if(n%7==0)
		
			min=n/7*2;
			max=n/7*2;
		  
		 else
		 
		 	if(n%7==1)
		 	
		 		max=n/7*2+1;
		 		min=n/7*2;
			 
			 else if(n%7>1&&n%7<=5)
			 
			 	max=n/7*2+2;
			 	min=n/7*2;
			 
			 else if(n%7==6)
			 
			 	max=n/7*2+2;
			 	min=n/7*2+1;
			 
		 
		 printf("%d %d\\n",min,max);
	
	return 0;