如何使用javascript在dropdownlist中使用方法?
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我必须通过从下拉列表中选择一个项目来显示/关闭字段。我在javacript中创建了一个函数,但它不能正常工作。这是我的下拉列表的代码:
<div id="payMethod" class="form-group">
<div class="row">
<div class="col-lg-12">
<label for="paymentMethod">Verificatiemethode</label>
<select class="btn btn-primary btn-block bg-primary" data-toggle="dropdown"
aria-haspopup="true" aria-expanded="false" id="paymentMethod" name="paymentMethod" onclick="showMethod()">
<option value="<?= $paymentRow['methode'] ?>"><?=$sellerRow['controle_optie_naam']?></option>
<?= $paymentList = getPaymentMethods($dbh) ?>
</select>
</div>
</div>
</div>
这是我用javascript编写的函数来从下拉列表中获取每个项目并使用该项目我试图隐藏/显示文本字段。
var payNumber = document.getElementById("payNumber");
var payMethod = document.getElementById("payMethod");
var bank = document.getElementById("selectBank");
var ccNumber = document.getElementById("ccNumber");
var sellerIndicBox = document.getElementById("sellerIndicBox");
var updateSeller = document.getElementById("updateSeller");
var paymentMethod = document.getElementById("paymentMethod");
var selectedValue =paymentMethod.options[paymentMethod.selectedIndex].value;
function showMethod(){
switch(selectedValue){
case "Creditcard":
payMethod.style.display = "block";
bank.style.display = "block";
ccNumber.style.display = "block";
updateSeller.style.display = "block";
payNumber.style.display = "none";
break;
case "Post":
payMethod.style.display = "block";
payNumber.style.display = "none";
bank.style.display = "none";
ccNumber.style.display = "none";
updateSeller.style.display = "none";
break;
case "iDeal":
payMethod.style.display = "block";
payNumber.style.display = "block";
bank.style.display = "block";
ccNumber.style.display = "none";
updateSeller.style.display = "none";
break;
default:
payMethod.style.display = "block";
payNumber.style.display = "block";
bank.style.display = "block";
ccNumber.style.display = "block";
updateSeller.style.display = "block";
}
}
答案
尝试将select的事件更改为onchange()
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